Question

我正在进行突破游戏。除了碰撞砖外，几乎所有的东西都完成了。到目前为止，当球击中砖时，砖块反弹但砖块不会消失。如果有人可以帮助我那会很棒。

主要课程：

public class Breakout extends Applet implements Runnable{
Thread thread = new Thread(this);
boolean running = true;
Brick2 b;
Paddle p;
Ball ba;
Image dbImage;
Graphics dbg;
public void init(){
    setSize(800,600);
    b = new Brick2();
    p = new Paddle(this);
    ba = new Ball(this);
}
public void start(){
    thread.start();
}
public void destroy(){
    running = false;
}
public void stop(){
    running = false;
}
public void run(){
    while(running){
        b.update(ba);
        p.update(this);
        ba.update(this,p);
        repaint();
        try{
            thread.sleep(20);
        }
        catch (InterruptedException e){
            System.out.println("AN ERROR HAS OCCURED");
        }
    }
}
public void update(Graphics g){
    dbImage = createImage(getWidth(),getHeight());
    dbg = dbImage.getGraphics();
    paint(dbg);
    g.drawImage(dbImage,0,0,this);
}
public void paint(Graphics g){
    g.fillRect(0,0,800,600);
    b.paint(g);
    p.paint(g,this);
    ba.paint(g,this);

}

}

砖类：

public class Brick2{
private int x;
private int y;

public Brick2(){

}
public void update(Ball ba){
    collision(ba);
}
public void collision(Ball ba){
    int bX = ba.getX();
    int bY = ba.getY();
    int bHeight = ba.getImageHeight();
    int bWidth = ba.getImageWidth();
    for(int x=0; x <= 800; x+=55){
        for (int y=0; y<= 100; y+=25){
           if (bX-bWidth<=x && bX+bWidth>=x && bY-bHeight<=y && bY+bHeight>=y){
               ba.setXVel(6);

            }
        }
    }
    }
    public int getX(){
    return x;
}
public int getY(){
    return y;
}
public void paint(Graphics g){
    for(int x=0; x <= 800; x+=55){
        for (int y=0; y<= 100; y+=25){
            g.setColor(Color.RED);
            g.fillRect(x,y,50,20);
        }
    }

} }

球类：

public class Ball {
private int x=355 ;
private int y=200;
private int speed = 6;
private int xVel = -speed;
private int yVel = speed;
private boolean gameOver = false;
private Image ball;
public Ball (Breakout bR){
    ball = bR.getImage(bR.getDocumentBase(),"ball.png");
    }
public void update(Breakout bR, Paddle p){
   x += xVel;
   y += yVel;
   if (x < 0){
       xVel = speed;
    }
   else if (x > bR.getWidth()){
        xVel = -speed;
    }
   if(y > bR.getHeight()){
       gameOver = true;
    }
   else if (y < 0){
        yVel = speed;
    }

   collision(p);
}
public void collision(Paddle p){
    int pX = p.getX();
    int pY = p.getY();
    int pHeight = p.getImageHeight();
    int pWidth = p.getImageWidth();

    if (pX<=x && pX+pWidth>=x && pY-pHeight<=y && pY+pHeight>=y){
       yVel = -speed;
    }
}
public int getX(){
    return x;
}
public int getY(){
    return y;
}
public int getImageWidth(){
    return ball.getWidth(null);
}
public int getImageHeight(){
    return ball.getHeight(null);
}
public void setXVel(int xv){
    yVel = xv;
}
public void paint (Graphics g, Breakout bR){
    g.drawImage(ball,x,y,bR);
    if (gameOver){
        g.setColor(Color.WHITE);
        g.drawString("Game Over", 100,300);
    }
}

}

感谢您的帮助。

Answer 1

如果检测到碰撞，Ball类的碰撞功能似乎没有发生任何事情。

之后

ba.setXVel(6);

你需要一些代码才能让砖不再画画。尝试在类定义中为砖提供可见性属性：

private Boolean visible;

在

之后的碰撞功能中

ba.setXVel(6);

插入

setVisible(false);

您需要为visible属性编写setter和getter。然后在paint函数中，将其设置为仅在可见为真时绘制。

您需要拥有多个Brick2实例。每个Brick2实例将代表一个单独的砖块。将它们放在像List这样的集合中，然后逐步绘制它们。

创建列表的一种方法是：

List<Brick2> bricks = new List<Brick2>;
for (i = 0; i > num_bricks; i++ ) {
    bricks.add(new Brick2());
}

但是你需要有办法设定每块砖的位置。也许基于砖号（i）并使用砖构造函数根据它们创建的顺序推导出它的位置。

在java中突破的砖碰撞

1 个答案: