Question

我需要知道如何通过JavaScript将日期传递到弹出页面并将其放在弹出窗口的<P>标记内？

<div class="header-img" align="center">

<img src="header.png" width="300">

</div>
<div class="maincontent" align="right">
<?php
include 'config.php';

$con->set_charset('utf8');
$sql = "SELECT * FROM de40v_subventions order by id desc";
$names = mysqli_query($con,$sql);
while($row = mysqli_fetch_array ($names)){


?>
<table class="maintable" align="right" width="400px" dir="rtl"> 
<form name="form" method="post" action="delconfirm.php" onSubmit="return checknone();">
<tr>
<td> <label> <b>الرقم: </b> </label> </td>
<td> <input type="text" value="<?php echo $row['id'] ?>" class="inputid" readonly/> </td>
</tr>
<tr>
<td> <label> <b>التاريخ والوقت: </b> </label> </td>
<td> <p> <?php echo date("Y-m-d H:m:s" , $row['datetime']); ?> </p> </td>
</tr>
<tr>
<td> <label> <b> الإسم كاملاً:</b> </label> </td>
<td> <p id="name"> <?php echo $row['firstname'] . ' ' . $row['fathername'] . ' ' . $row['grandfathername'] . ' ' . $row['familyname'] ?> </p> </td>
</tr>
<tr>
<td> <label> <b> رقم الهوية:</b> </label> </td>
<td> <p id="identity"> <?php echo $row['identity'] ?> </p> </td>

.........


<script type="text/JavaScript">

function openprint(){

    var popupwin = window.open("","طباعة البيانات","width=700, height=400");

    popupwin.document.writeln('<html><head><title>طباعة البيانات</title></head> <body> <center> <p id="printname"></p> </center> </body> </html>');
    popupwin.document.close();
    popupname = popupwin.document.getElementById('printname').innerHTML;
    name = document.getElementById('name').innerHTML;
    popupname = name;

}

<?php } ?>

Answer 1

实际上您的弹出页面上出现了一些内容，您还没有通过任何实际可见的内容。试试这个：

popupwin.document.getElementById('printname').innerHTML = 'put your date or content here';

将其放在writeln()来电之后。

循环时将数据通过JavaScript传递到弹出页面

1 个答案: