我有这段代码:
acceptAction = UIMutableUserNotificationAction()
acceptAction.identifier = "Accept"
acceptAction.title = "Accept"
acceptAction.activationMode = UIUserNotificationActivationModeForeground
acceptAction.destructive = false
acceptAction.authenticationRequired = false
let declineAction = UIMutableUserNotificationAction()
declineAction.identifier = "Decline"
declineAction.title = "Decline"
declineAction.activationMode = UIUserNotificationActivationMode.Background
declineAction.destructive = false
declineAction.authenticationRequired = false
当我以
运行时mpiexec -n 2 MPI.exe
该计划有效;输出是:
#include <cstdint>
#include <mpi.h>
#include <iostream>
using namespace std;
int main(int argc, char **argv)
{
MPI_Init(&argc, &argv);
int rank;
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
if (rank == 0)
MPI_Barrier(MPI_COMM_WORLD);
cout << "Some output\n";
if (rank == 1)
MPI_Barrier(MPI_COMM_WORLD);
MPI_Barrier(MPI_COMM_WORLD);
cout << "end\n";
MPI_Finalize();
return 0;
}
然而,当我以
运行时mpiexec -n 3 MPI.exe
程序不正常工作。我期望这样的输出:
Some output
End
Some output
End
在此步骤中,我希望程序停止。
答案 0 :(得分:3)
您需要确保每个进程的屏障调用次数相同。在您的特定情况下,当n = 3时,您对等级0和等级1有两个障碍调用,但对于等级2只有1个。程序将阻塞,直到等级2过程也达到障碍。
以下是n = 3应该发生的事情:
together:
rank 0 will reach barrier 1 then block
rank 1 will print "some output", reach barrier 2 then block
rank 2 will print "some output", reach barrier 3 then block
together:
rank 0 will print "some output", reach barrier 3 then block
rank 1 will reach barrier 3 then block
rank 2 will print "end" then hit finalize
有一个进程在finalize中而其他进程被阻塞将是未定义的行为。
对n = 2进行相同的分析:
together:
rank 0 will reach barrier 1 then block
rank 1 will print "some output", reach barrier 2 then block
together:
rank 0 will print "some output", reach barrier 3 then block
rank 1 will reach barrier 3 then block
together:
rank 0 will print "end" then hit finalize
rank 1 will print "end" then hit finalize
这表明输出应为:
some output
some output
end
end
但是你得到了:
some output
end
some output
end
这与mpi基础设施如何缓存各级别的stdout传输有关。如果我们引入延迟以便MPI决定它应该收集结果,我们可以更好地看到行为:
#include <cstdint>
#include <unistd.h>
#include <mpi.h>
#include <iostream>
using namespace std;
int main(int argc, char **argv)
{
MPI_Init(&argc, &argv);
int rank;
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
if (rank == 0) {
cout << rank << " Barrier 1\n" << flush;
MPI_Barrier(MPI_COMM_WORLD);
}
cout << rank << " Some output \n" << flush;
usleep(1000000);
if (rank == 1) {
cout << rank << " Barrier 2\n" << flush;
MPI_Barrier(MPI_COMM_WORLD);
}
cout << rank << " Barrier 3\n" << flush;
MPI_Barrier(MPI_COMM_WORLD);
cout << rank << " end\n" << flush;
usleep(1000000);
MPI_Finalize();
return 0;
}
产生:
$ mpiexec -n 2 ./a.out
0 Barrier 1
1 Some output
0 Some output
1 Barrier 2
1 Barrier 3
0 Barrier 3
0 end
1 end
$ mpiexec -n 3 ./a.out
2 Some output
0 Barrier 1
1 Some output
0 Some output
1 Barrier 2
1 Barrier 3
2 Barrier 3
2 end
0 Barrier 3
^Cmpiexec: killing job...
或者,查看以下C ++ 11代码中的时间戳:
#include <cstdint>
#include <chrono>
#include <mpi.h>
#include <iostream>
using namespace std;
inline unsigned long int time(void) {
return std::chrono::high_resolution_clock::now().time_since_epoch().count();
}
int main(int argc, char **argv)
{
MPI_Init(&argc, &argv);
int rank;
MPI_Comm_rank(MPI_COMM_WORLD, &rank);
if (rank == 0) {
MPI_Barrier(MPI_COMM_WORLD);
}
cout << rank << " " << time() << " Some output\n";
if (rank == 1) {
MPI_Barrier(MPI_COMM_WORLD);
}
MPI_Barrier(MPI_COMM_WORLD);
cout << rank << " " << time() << " end\n";
MPI_Finalize();
return 0;
}
输出:
$ mpiexec -n 2 ./a.out
0 1464100768220965374 Some output
0 1464100768221002105 end
1 1464100768220902046 Some output
1 1464100768221000693 end
按时间戳排序:
$ mpiexec -n 2 ./a.out
1 1464100768220902046 Some output
0 1464100768220965374 Some output
1 1464100768221000693 end
0 1464100768221002105 end
结论是障碍表现得如预期,并且印刷声明不一定会告诉你。
编辑:2016-05-24显示程序行为的详细分析。