Question

我已编写此代码来计算二次公式：

from numpy.lib.scimath import sqrt as csqrt

a = raw_input("a?")

b = raw_input("b?")

c = raw_input("c?")

def numcheck(x):
    try:
       i = float(x)
       return True
    except (ValueError, TypeError):
       return False

if numcheck(a)==True:
    a=int(a)
else:
    print "a is not a number"

if numcheck(b)==True:
    b=int(b)
else:
    print "b is not a number"

if numcheck(c)==True:
    c=int(c)
else:
    print "b is not a number"


sqrt= ((b*b) - (4* (a*c)))

x_minus= (-b+(csqrt(sqrt)))/(2*a)
x_minus=str(x_minus)

x_plus= (-b-(csqrt(sqrt)))/(2*a)
x_plus=str(x_plus)

print "The solution is "+x_plus+" or "+x_minus

从不关注相当糟糕的风格，当输入不是数字时，我收到此错误：

Traceback (most recent call last):
File "build\bdist.win32\egg\IPython\core\ultratb.py", line 776, in structured_traceback
File "build\bdist.win32\egg\IPython\core\ultratb.py", line 230, in wrapped
File "build\bdist.win32\egg\IPython\core\ultratb.py", line 267, in _fixed_getinnerframes
UnicodeDecodeError: 'ascii' codec can't decode byte 0xba in position 51: ordinal not in range(128)
ERROR: Internal Python error in the inspect module.
Below is the traceback from this internal error.

Unfortunately, your original traceback can not be constructed.

任何人都可以告诉我为什么会这样，如果可能的话，还有办法解决这个问题吗？感谢。

Answer 1

要做一个sqrt，你可以这样做：

def sqrt(num):
    return num ** 0.5

我会尝试为您提供与您的问题相关的更多信息，但现在尝试用您的sqrt替换您的sqrt。

Python 2错误：“检查模块中的内部Python错误

1 个答案: