Question

我在edx python课程中被分配来创建一个程序，该程序打印出从给定字符串开始按字母顺序排列的最长子字符串。我编写了我的代码，但是当我运行它时，我得到了＃34;错误：检查模块中的内部Python错误。＆＃34;。我不明白为什么。如果有人能帮助我搞清楚它会很棒。这是代码：

s = 'azcbobobegghakl'
start=0
temp=0
while start<len(s):
    initial=start
    while True:
        if ord(s[start])<=ord(s[start+1]):
            start+=1
        else:
            start+=1
            if len(s[initial:start])>temp:
                sub=s[initial:start]
                temp=len(sub)
            break    
print sub

这是完整的错误：

Traceback (most recent call last):
  File "C:\Users\Yoav\AppData\Local\Enthought\Canopy\App\appdata\canopy-1.5.4.3105.win-x86_64\lib\site-packages\IPython\core\ultratb.py", line 776, in structured_traceback
    records = _fixed_getinnerframes(etb, context, tb_offset)
  File "C:\Users\Yoav\AppData\Local\Enthought\Canopy\App\appdata\canopy-1.5.4.3105.win-x86_64\lib\site-packages\IPython\core\ultratb.py", line 230, in wrapped
    return f(*args, **kwargs)
  File "C:\Users\Yoav\AppData\Local\Enthought\Canopy\App\appdata\canopy-1.5.4.3105.win-x86_64\lib\site-packages\IPython\core\ultratb.py", line 267, in _fixed_getinnerframes
    if rname == '<ipython console>' or rname.endswith('<string>'):
UnicodeDecodeError: 'ascii' codec can't decode byte 0xe9 in position 3: ordinal not in range(128)
ERROR: Internal Python error in the inspect module.
Below is the traceback from this internal error.


Unfortunately, your original traceback can not be constructed.

谢谢！

Answer 1

看起来代码大部分都有效，但是当你调用break时，它只会中断else块，并继续运行while，其start值大于s的max索引。

尝试将此代码放在函数中，并在找到正确的子字符串时使用return

祝你好运！

def sub_finder(s):

start=0
temp=0
while start<len(s):
    initial=start
    while True:
        if (start < len(s) - 1):
            if ord(s[start])<=ord(s[start+1]):
                start+=1
            else:
                start+=1
                if len(s[initial:start])>temp:
                    sub=s[initial:start]
                    temp=len(sub)
                break
        else:
            start+=1
            if len(s[initial:start])>temp:
                sub=s[initial:start]
                temp=len(sub)
            return sub

test = 'abcdaabcdefgaaaaaaaaaaaaaaaaaaaaaaaaaaaabbcdefg'
print sub_finder(test)

哎呀，试试这个大小。

错误：检查模块

1 个答案: