如何将var vid = document.getElementById('myvid'),
ticks = 50, // number of frames during fast-forward
frms = 10, // number of milleseconds between frames in fast-forward/rewind
endtime = 24.0; // time to fast-forward/remind to (in seconds)
// fast-forward/rewind video to end time
var tdelta = (endtime - vid.currentTime)/ticks;
for ( var i = 0; i < ticks; ++i )
{
(function(j){
setTimeout(function() {
vid.currentTime = vid.currentTime + tdelta * j;
}, j * frms);
})(i);
}
(datetime64 [ns])和Day
(int64)合并到一个日期时间列中?
Hour
答案 0 :(得分:6)
df = pd.DataFrame({
'Day': np.array(['2010-04-24', '2012-08-20', '2016-03-06', '2016-01-02', '2010-12-21'], dtype=np.datetime64),
'Hour': np.array([17, 10, 9, 10, 4], dtype=np.int64)})
>>> pd.to_datetime(df.Day) + pd.to_timedelta(df.Hour, unit='h')
0 2010-04-24 17:00:00
1 2012-08-20 10:00:00
2 2016-03-06 09:00:00
3 2016-01-02 10:00:00
4 2010-12-21 04:00:00
dtype: datetime64[ns]
答案 1 :(得分:1)
使用此列表推导创建一个使用dt.timedelta添加一小时到一天的列:
data = {'Day':pd.to_datetime(['2010-04-24','2012-08-20','2016-03-06','2016-01-02','2010-12-21']),'Hour':[17,10,9,10,4]}
df = pd.DataFrame(data)
df['Datetime'] = [df.loc[x,'Day'] + dt.timedelta(hours = int(df.loc[x,'Hour'])) for x in list(df.index)]
这假设Day列的小时/分钟/秒都是00:00:00
返回
Day Hour Datetime
2010-04-24 17 2010-04-24 17:00:00
2012-08-20 10 2012-08-20 10:00:00
2016-03-06 9 2016-03-06 09:00:00
2016-01-02 10 2016-01-02 10:00:00
2010-12-21 4 2010-12-21 04:00:00