如何在多维数组中计算包含零的COLUMNS的数量。 我能够计算包含零的行数,但我无法理解如何计算列数。请帮忙。
public class Main {
public static void main (String[] args) {
int i;
int j;
int count = 0;
int [][] arr = {{3, 0, 0, 6}, {4, 0, 1, 1}};
for (i = 0; i < arr.length; i++) {
System.out.println();
for (j = 0; j < arr[i].length; j++){
System.out.print(arr[i][j] + ", ");
}
}
System.out.println();
//-----------------------------------------------------------
for (i = 0; i<arr.length; i++) {
for (j = 0; j<arr[i].length; j++) {
if (arr[i][j] == 0) {
count++;
break;
}
}
}
System.out.println("the amount of rows containing zeros = " + count);
}
}
答案 0 :(得分:1)
另一种直接获得sqaure矩阵相同结果的方法:
import java.util.*;
import java.lang.*;
import java.io.*;
/* Name of the class has to be "Main" only if the class is public. */
class Ideone
{
public static void main (String[] args) throws java.lang.Exception
{
int i;
int j;
int count = 0;
int [][] arr = {{3, 0, 0, 6}, {4, 0, 1, 0}};
for (i = 0; i < arr.length; i++)
{
System.out.println();
for (j = 0; j < arr[i].length; j++)
{
System.out.print(arr[i][j] + ", ");} }
System.out.println();
//--------------------------------------------------------------------
for (i = 0; i<arr.length; i++)
for (j = 0; j<arr[i].length; j++)
if (arr[i][j] == 0)
{
count++;
break;
}
System.out.println("the amount of rows containing zeros = " + count);
//--------------------------------------------------------------------
count=0;
for (i = 0; i<arr[0].length; i++)
for (j = 0; j<arr.length; j++)
if (arr[j][i] == 0)
{
count++;
break;
}
System.out.println("the amount of cols containing zeros = " + count);
}
}
输出:
3, 0, 0, 6,
4, 0, 1, 0,
the amount of rows containing zeros = 2
the amount of cols containing zeros = 3