Question

考虑一个向量，A = [0.13,0.98,0.05]

如何绘制矢量，B与A平行但在点处 P = [155,156,52]，是载体B的起源。

我在MATLAB中尝试如下，

pts = [O; A]; %   O= [0 0 0]
line(pts(:,1), pts(:,2), pts(:,3))

B = A*10; % Multiplied B by any scalar (e.g. 10) to get a vector parallel to A  
hold on
pts = [P; B]; % PB vector parallel to OA
line(pts(:,1), pts(:,2), pts(:,3))

你能纠正我吗？

％******************更多解释********

         E = cross(B,C);

所以三个向量（B，E，C）需要在P点绘制。我完全被困在这里

Answer 1

你有第一个线段和矢量点（它定义了段的方向和它的长度）。

要获得第二个点，您必须将向量添加到第一个点：

pts = [P; P + B];
for your data
P = [155, 156, 52]
B =  [1.3, 9.8, 0.5]
P + B = [156.3, 165.8, 52.5]

Vector / Point算术的一些规则：

Vector = Point - Point
there is no point addition operation
Point = Point +/- Vector
Vector = Vector +/- Vector
Vector = Scalar * Vector
//more complex rules for multiplication

在两个彼此平行的点上绘制两个向量

1 个答案: