我在这两个案例中遇到问题print daysBetweenDates(2011, 1, 1, 2012, 8, 8)
print daysBetweenDates(1900,1,1, 1999,12, 31)当我把它们与其他测试案例放在一起时，我得到了错误的答案，额外1天，有时候是2天。有时候其中一个给了我正确答案但是它也显示为Test with data:(2011, 1, 1, 2012,8,8)failed
Test with data: (1900, 1, 1, 1999, 12, 31) failed，但当我单独测试每个案例时，我得到了正确答案。
daysofmonths = [ 0,31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
def leap_year(year):
leap_day = 366
common_day = 365
if year % 4 != 0:
return common_day
elif year % 100 != 0:
return leap_day
elif year % 400 !=0:
return common_day
else:
return leap_day
def daysBetweenDates(year1, month1, day1, year2, month2, day2):
#code for same year
if year1 == year2:
if month1 == month2:
return day2 - day1
days = daysofmonths[month1] - day1
month1 = month1 + 1
while month1 < month2:
if leap_year(year1) == 366:
daysofmonths[2] = 29
days = days + daysofmonths[month1]
month1 = month1 + 1
return days + day2
################################################
days = daysofmonths[month1] - day1
month1 = month1 + 1
while month1 <= 12:
if leap_year(year1) == 366:
daysofmonths[2] = 29
days = days + daysofmonths[month1]
month1 = month1 + 1
#print days
year1 = year1 + 1
###########################################################
days = days + day2
month2 = month2 - 1
while month2 >= 1:
if leap_year(year2) == 366:
daysofmonths[2] = 29
days = days + daysofmonths[month2]
month2 = month2 - 1
#print days
year2 = year2 - 1
###########################################################
while year1 <= year2:
days = days + leap_year(year1)
year1 = year1 + 1
return days
print daysBetweenDates(2011, 1, 1, 2012, 8, 8)
print daysBetweenDates(1900,1,1, 1999,12, 31)
def test():
test_cases = [((2012,1,1,2012,2,28), 58),
((2012,1,1,2012,3,1), 60),
((2011,6,30,2012,6,30), 366),
((2011,1,1,2012,8,8), 585 ),
((1900,1,1,1999,12,31), 36523)]
for (args, answer) in test_cases:
result = daysBetweenDates(*args)
if result != answer:
print "Test with data:", args, "failed"
else:
print "Test case passed!"
test()
答案 0 :(得分：0)
当你这样做时：
daysofmonths[2] = 29
它会更改列表中的元素，然后用于每个后续调用，如果您在测试用例之间添加print(daysofmonths[2])，您会看到在第一个案例之后始终为29需要检查二月，所以不要有条件地改变列表：
if leap_year(year1) == 366:
daysofmonths[2] = 29
days = days + daysofmonths[month1]
只是有条件地添加到days：
if leap_year(year1) == 366 and month1 == 2:
days = days + 29
else:
days = days + daysofmonths[month1]
然后使用year2和month2执行同样的操作（我强烈建议您将代码分成更多功能，因为很多功能非常重复）
答案 1 :(得分：0)
这是我在这个特定问题上找到的唯一一篇帖子，所以我想我会分享我的解决方案。
#days in the months of a non leap year
daysOfMonths = [31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31]
#determine if a year is a leap year
def is_leap_year(year1):
year = True
if year1 % 4 != 0:
year = False
elif year1 % 100 != 0:
year = True
elif year1 % 400 != 0:
year = False
else: year = True
return year
#returns the days in the given month of the given year
#I was trying to do something similar to the OP until I read this post
def days_in_month(year, month):
days = 0
if is_leap_year(year) and month == 2:
days += 29
else:
days += daysOfMonths[month - 1]
return days
#itterates through each month starting at year1 month1
#up to but not including month2 of year2 and
#returns the total number of days in that period
def total_days(year1, month1, year2, month2):
days = 0
while year1 < year2 or month1 < month2:
days += days_in_month(year1, month1)
month1 += 1
if month1 == 13:
year1 += 1
month1 = 1
return days
def daysBetweenDates(year1, month1, day1, year2, month2, day2):
days = total_days(year1, month1, year2, month2)
#because I included the beginning month I have to subtract day1
#because I did not include the final month I have to add day2
return days - day1 + day2
#I used print statements here to troubleshoot
#print days_in_month(2012, 1)
#print daysBetweenDates(2012, 1, 1, 2012, 2, 28)
#print daysBetweenDates(2012, 1, 1, 2012, 3, 1)
#print daysBetweenDates(2011,6,30,2012,6,30)
#print daysBetweenDates(2011,1,1,2012,8,8)
#print daysBetweenDates(1900,1,1,1999,12,31)
def test():
test_cases = [((2012,1,1,2012,2,28), 58),
((2012,1,1,2012,3,1), 60),
((2011,6,30,2012,6,30), 366),
((2011,1,1,2012,8,8), 585 ),
((1900,1,1,1999,12,31), 36523)]
for (args, answer) in test_cases:
result = daysBetweenDates(*args)
if result != answer:
print "Test with data:", args, "failed"
else:
print "Test case passed!"
test()