Question

我创建了一个包含6个数字的数组。我已生成1到40之间的随机数，但每个数字都按顺序显示。我需要它只读6

        static void Main()
    {
        int temp;
        int number = 0;
        int[] lotto = new int[6];

        Random rand = new Random();

        for (int i = 0; i <= 40; i++)
        {
            number = 0;
            temp = rand.Next(1, 40);

            while (number <= i)
            {
                if (temp == number)
                {
                    number = 0;
                    temp = rand.Next(1, 40);
                }
                else
                {
                    number++;
                }                    
            }
            temp = number;
            Console.WriteLine("your lotto number is " + number);
        }
            Console.ReadLine(); 
    }
}

}

Answer 1

试试这个

        int number = 0;
        int[] lotto = new int[6];

        Random rand = new Random();

        for (int ctr = 1; ctr <= 6; ctr++)
        {
            number = rand.Next(1, 41);

            while (lotto.Contains<int>(number))
            {
                number = rand.Next(1, 41);
            }
            lotto[ctr-1] = number;
            Console.WriteLine("Your lotto number is: " + number);
        }

        Console.ReadLine();

如果你想对它进行排序，你可以像这样做 int[] sortedCopy = lotto.OrderBy(i => i).ToArray();
但是你需要
using System.Linq;

Answer 2

按Guid.NewGuid()订购的简单Linq？

var lotto = Enumerable.Range(1, 40)
                      .OrderBy(i => Guid.NewGuid())
                      .Take(6)
                      .ToArray();

乐透游戏Visual Studio

2 个答案: