使用SQL和PHP进行多次INSERT / UPDATE

时间：2016-03-30 18:02:20

标签： php mysql sql sql-insert

你可以建议我同时进行多次INSERT和UPDATE的最佳解决方案吗？

我使用SELECT从表中检索记录，如果用户选中“insert”复选框，我会让用户更新每条记录的内容。 目前，我为每组记录使用表单按钮。

由于可能有很多记录，我想只为所有数据使用一个“表单”和一个“表单按钮”，并在用户选中复选框时仅更新或插入记录集。可能吗？如果有，怎么样？你能给我任何建议吗？

$sql = "select * from table1 where nome_area like '%$nome_area%' AND nome_voce like '%$nome_voce%'";

    $rs = mysql_query( $sql ) or die('Database Error: ' . mysql_error());
    $num = mysql_num_rows( $rs );

    if($num >= 1 ){         

        echo "<table align=\"center\" cellspacing=0 cellpadding=100>";

        echo "<tbody><tr><td width=\"20%\">&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;</td><td>";

        while($row = mysql_fetch_array( $rs )){

            echo "<form name=\"form\" id=\"form\" action=\"update.php\" method=\"post\">";
        echo "<table data-role=\"table\" class=\"ui-responsive\"  cellspacing=\"20\" ";
        echo "<tbody>";

            echo "<tr>";
            echo "<td>";
            echo "<font text color=\"red\">Insert</font> &nbsp;&nbsp;&nbsp;</td><td><input type=\"checkbox\"  name=\"insert\" value=\"1\" id=\"insert\"></td></tr>";
            echo "<tr><td><b>Tipo Area</b>:</td><td>".$row['nome_area']. " </td></tr><tr><td><b>Nome della voce</b>: </td><td> " .$row['nome_voce'] . "</td></tr>";
echo "<tr><td>";
            echo "<input type=\"hidden\" style=\"width:0; height:0; border:0; background-color:inherit; overflow:hidden;\" name=\"id_voce\"  maxlength=\"50\" value=\"" . $row['ID'] . "\">";
            echo "<input type=\"hidden\" style=\"width:0; height:0; border:0; background-color:inherit; overflow:hidden;\" name=\"nome_azienda\"  maxlength=\"50\" value=\"" .$name. "\">"; // azienda
            echo "<input type=\"hidden\" style=\"width:0; height:0; border:0; background-color:inherit; overflow:hidden;\" name=\"nome_area\"  maxlength=\"50\" value=\"" .$row['nome_area']. "\">";
            echo "<input type=\"hidden\" style=\"width:0; height:0; border:0; background-color:inherit; overflow:hidden;\" name=\"nome_voce\"  maxlength=\"50\" value=\"" .$row['nome_voce']. "\">";
            echo "</td></tr>";
            echo "<tr><td colspan=\"2\"> <input type=\"submit\" value=\"Associa la voce di contratto all'azienda\" id=\"search-btn\" style=\"height:50px; \"; /></td></tr>";
            echo "</tbody></table>";
                echo "</form>";



}

echo "</td></tr></tbody></table>";

    }else{
        // if no records found
        echo "<br><br><b>Nessun risultato trovato!</b></div>";
    }

在我的update.php页面中，我只是读取了表单值并将它们插入到我的表中：

.....
mysql_query("INSERT INTO table2 (id_voce,associazione, nome_azienda, nome_area, nome_voce, created_date) VALUES('$id_voce','$associa','$nome_azienda','$nome_area','$nome_voce','$time')");

3 个答案:

答案 0 :(得分：1)

一种方法是为每一行生成一个顺序行id＃。我们假设这是您从数据库中收集的行：

$rs = array(
    array('ID'=>'111', 'nome_area'=>'first nome area',  'nome_voce'=>'first nome voce'),
    array('ID'=>'222', 'nome_area'=>'second nome area', 'nome_voce'=>'second nome voce'),
    array('ID'=>'333', 'nome_area'=>'third nome area',  'nome_voce'=>'third nome voce'),
);

现在使用具有顺序ID号的复选框创建表：

$rowcounter = 0;
foreach ($rs as $row) {
    $rowcounter++;
    echo <<<HERE
<tr>
  <td><input type="checkbox" name="row_{$rowcounter}_checkbox" value="1" /></td>
  <td>
    ID: {$row['ID']}
    <input type="hidden" name="row_{$rowcounter}_ID" value="{$row['ID']}" />
  </td>
  <td>
    Tipo Area: {$row['nome_area']}
    <input type="hidden" name="row_{$rowcounter}_nome_area" value="{$row['nome_area']}" />
  </td>
  <td>
    Nome della voce: {$row['nome_voce']} 
    <input type="hidden" name="row_{$rowcounter}_nome_voce" value="{$row['nome_voce']}" />
  </td>
</tr>

HERE;
}

提交表单后，您可以找到所有选中的复选框，然后处理与该唯一行ID相关的其他表单值：

foreach ($_POST as $key=>$val) {
    if (preg_match("/^row_(\d+)_checkbox$/",$key,$matches) && $val == "1") {

        $rowid = $matches[1];

        $ID = $_POST["row_{$rowid}_ID"];
        $nome_area = $_POST["row_{$rowid}_nome_area"];
        $nome_voce = $_POST["row_{$rowid}_nome_voce"];

        print "The checkbox was checked for the row with this data:\n";
        print "ID: $ID\n";
        print "nome_area: $nome_area\n";
        print "nome_voce: $nome_voce\n";
    }
}

编辑对于您自己的HTML代码，它将是这样的：

$rowcounter = 0;
echo "<form name=\"form\" id=\"form\" action=\"update.php\" method=\"post\">";
echo "<table data-role=\"table\" class=\"ui-responsive\"  cellspacing=\"20\" ";
echo "<tbody>";
while($row = mysql_fetch_array( $rs )){
    $rowcounter++;
    echo "<tr>";
    echo "<td>";
    echo "<font text color=\"red\">Insert</font> &nbsp;&nbsp;&nbsp;</td><td><input type=\"checkbox\"  name=\"row_{$rowcounter}_insert\" value=\"1\" id=\"insert\"></td></tr>";
    echo "<tr><td><b>Tipo Area</b>:</td><td>".$row['nome_area']. " </td></tr><tr><td><b>Nome della voce</b>: </td><td> " .$row['nome_voce'] . "</td></tr>";
    echo "<tr><td>";
    echo "<input type=\"hidden\" style=\"width:0; height:0; border:0; background-color:inherit; overflow:hidden;\" name=\"row_{$rowcounter}_id_voce\"  maxlength=\"50\" value=\"" . $row['ID'] . "\">";
    echo "<input type=\"hidden\" style=\"width:0; height:0; border:0; background-color:inherit; overflow:hidden;\" name=\"row_{$rowcounter}_nome_azienda\"  maxlength=\"50\" value=\"" .$name. "\">"; // azienda
    echo "<input type=\"hidden\" style=\"width:0; height:0; border:0; background-color:inherit; overflow:hidden;\" name=\"row_{$rowcounter}_nome_area\"  maxlength=\"50\" value=\"" .$row['nome_area']. "\">";
    echo "<input type=\"hidden\" style=\"width:0; height:0; border:0; background-color:inherit; overflow:hidden;\" name=\"row_{$rowcounter}_nome_voce\"  maxlength=\"50\" value=\"" .$row['nome_voce']. "\">";
    echo "</td></tr>";
}
echo "<tr><td colspan=\"2\"> <input type=\"submit\" value=\"Associa la voce di contratto all'azienda\" id=\"search-btn\" style=\"height:50px; \"; /></td></tr>";
echo "</tbody></table>";
echo "</form>";

和这样的表单处理器：

foreach ($_POST as $key=>$val) {
    if (preg_match("/^row_(\d+)_insert$/",$key,$matches)) {
        $rowid = $matches[1];
        $nome_id_voce = $_POST["row_{$rowid}_nome_id_voce"];
        $nome_area    = $_POST["row_{$rowid}_nome_area"];
        $nome_voce    = $_POST["row_{$rowid}_nome_voce"];
    }
}

答案 1 :(得分：0)

使用ON DUPLICATE KEY UPDATE语法执行新记录的插入或现有记录的更新（基于PK）

答案 2 :(得分：0)

您需要将记录ID添加到元素名称。例如：

echo "<input type=\"hidden\" style=\"width:0; height:0; border:0; background-color:inherit; overflow:hidden;\" name=\"nome_voce_". $row['ID'] ."\"  maxlength=\"50\" value=\"" .$row['nome_voce']. "\">";

您可以在update.php中获取所有变量并准备多个insert命令。 还有基于js的表编辑器，你可以使用它们。简单的一个：http://codepen.io/ashblue/pen/mCtuA

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