我需要帮助编写一个条件查询来将数据从一个表复制到另一个表,一切都非常直接,直到我决定在我的应用程序中包含版本控制!
我已经看了一些例子,但是他们主要是为了创建一个mysql程序,这就是我试过的:
SELECT CASE
WHEN NOT EXISTS (
SELECT `version`
FROM `archive_courses`
WHERE `original_course_id` = '$course_id'
AND `version` = '$current_version'
)
THEN
BEGIN
INSERT INTO `archive_course_users` <------ syntax error
(`course_id`, `user_id`, `course_qty`)
SELECT @new_course_id, '$user_id', `course_qty`
FROM `current_course_users`
WHERE `course_id` = '$course_id'
AND `user_id` = '$user_id'
END
ELSE
BEGIN
UPDATE `archive_course_users`
SET `course_qty` = (SELECT `course_qty` FROM `current_course_users` WHERE `user_id` = '$user_id')
WHERE `original_course_id` = '$course_id'
AND `user_id` = '$user_id'
END
END
END
似乎情况正常/确定/但是当它到达我的INSERT
查询时会抛出语法错误。 我该怎么做?
答案 0 :(得分:1)
它不应该那样工作。将您的查询更改为
INSERT INTO `archive_course_users`
(`course_id`, `user_id`, `course_qty`)
SELECT @new_course_id, '$user_id', `course_qty`
FROM `current_course_users`
WHERE `course_id` = '$course_id'
AND `user_id` = '$user_id'
AND NOT EXISTS (
SELECT 1
FROM `archive_courses`
WHERE `original_course_id` = '$course_id'
AND `version` = '$current_version');
答案 1 :(得分:0)
你试过"insert.. on duplicate key update"
吗?
以下是mysql手册中的一个例子:
INSERT INTO table (a,b,c) VALUES (1,2,3)
ON DUPLICATE KEY UPDATE c=c+1;
UPDATE table SET c=c+1 WHERE a=1;
http://dev.mysql.com/doc/refman/5.7/en/insert-on-duplicate.html
希望有所帮助
答案 2 :(得分:0)
根据@ Rahul的回答,我创建了两个查询:
//INSERT IF NOT EXISTS
INSERT INTO `archive_course_users`
(`course_id`, `user_id`, `course_qty`)
SELECT @new_course_id, '$user_id', `course_qty`
FROM `current_course_users`
WHERE NOT EXISTS (
SELECT `version`
FROM `archive_courses`
WHERE `original_course_id` = '$course_id'
AND `version` = '$current_version'
)
AND `course_id` = '$course_id'
AND `user_id` = '$user_id'
//UPDATE IF EXISTS
UPDATE `archive_course_users`
SET `course_qty` = (SELECT `course_qty` FROM `current_course_users` WHERE `user_id` = '$user_id')
WHERE EXISTS (
SELECT `version`
FROM `archive_courses`
WHERE `original_course_id` = '$course_id'
AND `version` = '$current_version'
)
AND `original_course_id` = '$course_id'
AND `user_id` = '$user_id'
答案 3 :(得分:0)
SELECT
内无法包含语句。所以要么
将代码移出SELECT
:
IF (...) THEN -- Note: No "CASE"; not "WHEN"
INSERT ...
ELSE
UPDATE
END IF
或SELECT
某种标志,然后在外面使用IF
语句。