使用类

Question

我试图用类创建一个经典的tic tac toe游戏。我通过默认构造函数建立了我的数组，当我尝试从类中的另一个公共函数显示游戏板时，我会得到像这样的随机符号＆＃39;＆amp;♥＆＃39;。 （我知道我缺少功能，除了我无法解决这个问题！）这是我的程序输出：OUTPUT和程序：

＆＃13;

＆＃13;

class TicTacToe
{
	private:
		char board[3][3];
		char player;
		
	public:
		void getBoard();
		char changePlayer(char);
		void setPosition(int, int);
		TicTacToe();
};

int main ()
{
	bool endOfGame = false;
	int rows;
	int columns;
	int test;
	TicTacToe ttt;

	while (!endOfGame)
	{
		cout << "Please enter the row number: ";
		cin >> rows;
		cout << "Please enter the column number: ";
		cin >> columns;
		
		ttt.setPosition(rows, columns);
		ttt.getBoard();
	}



	return 0;
}


TicTacToe::TicTacToe()
{
	char board[3][3] = {'*','*','*',
						'*','*','*',
						'*','*','*',};
	player = 'x';
}

void TicTacToe::getBoard()
{			     
	for (int i = 0; i < 3; i++)
	{
		for (int c = 0; c < 3; c++)
		{
			cout << board[i][c];
		}
	cout << endl;
	}
}

char TicTacToe::changePlayer(char choice)
{
}

void TicTacToe::setPosition(int row, int column)
{
	if (player == 'x')
	{ board[row][column] = 'x'; }
	
	else
	{ board[row][column] = 'o'; }

}

＆＃13;

＆＃13;

＆＃13;

Answer 1

您永远不会初始化您的类成员数组。构造函数中的数组是本地对象。一个简单的解决方案是使用类内初始化器并删除构造函数：

class TicTacToe
{
    private:
        char board[3][3] {'*','*','*','*','*','*','*','*','*'};
        char player {'x'};

    public:
        void getBoard();
        char changePlayer(char);
        void setPosition(int, int);
};

编辑，当你需要一个构造函数时使用初始化列表（从c ++ 11开始）：

TicTacToe::TicTacToe()
    : board {'*', '*', '*', '*', '*', '*', '*', '*', '*'}
{}

Answer 2

解决方案：

TicTacToe::TicTacToe()
{
	for (int i = 0; i < 3; i++)
	{
		for (int c = 0; c < 3; c++)
		{
			board[i][c] = '*';
		}
	cout << endl;
	}
	
	player = 'x';
}

void TicTacToe::getBoard()
{	
	cout << "\n" << board[0][0] << " | " << board[0][1] << " | " << board[0][2];
	cout << "\n" << "---------";
	cout << "\n" << board[1][0] << " | " << board[1][1] << " | " << board[1][2];
	cout << "\n" << "---------";
	cout << "\n" << board[2][0] << " | " << board[2][1] << " | " << board[2][2];
	cout << endl << endl;

}