y是每2分钟时间内火车站平台的乘客数量,而A1至A17是广场上17个研究区域的乘客数量。通过改变X来考虑时间滞后。 有时,在大厅的研究区域内没有人等待,所以会出现过零。我计划使用零膨胀模型。我已经尝试过如下所示的代码,但它说“最小计数不为零”这意味着什么,我该如何解决?我已经完成了poisson,它没关系,但零膨胀不起作用。
> setwd('C:/Users/zuzymelody/Desktop')
> try<-read.csv('0inflated_2mins27peak.csv',header=TRUE)
> attach(try)
> names(try)
[1] "y" "A1" "A2" "A3" "A4" "A5" "A6" "A7" "A8" "A9" "A10" "A11"
[13] "A12" "A13" "A14" "A15" "A16" "A17"
> model1<-glm(y~A1+A2+A3+A4+A5+A6+A7+A8+A9+A10+A11+A12+A13+A14+A15+A16+A17,family="poisson")
> summary(model1)
Call:
glm(formula = y ~ A1 + A2 + A3 + A4 + A5 + A6 + A7 + A8 + A9 +
A10 + A11 + A12 + A13 + A14 + A15 + A16 + A17, family = "poisson")
Deviance Residuals:
Min 1Q Median 3Q Max
-7.8598 -3.4571 -0.3663 2.1867 12.5183
Coefficients:
Estimate Std. Error z value Pr(>|z|)
(Intercept) 6.102009 0.164497 37.095 < 2e-16 ***
A1 -0.017555 0.003665 -4.790 1.66e-06 ***
A2 -0.026101 0.017569 -1.486 0.137371
A3 -0.179988 0.014976 -12.018 < 2e-16 ***
A4 -0.032584 0.007735 -4.213 2.52e-05 ***
A5 -0.019908 0.007014 -2.839 0.004532 **
A6 -0.044144 0.010266 -4.300 1.71e-05 ***
A7 0.049829 0.006518 7.645 2.09e-14 ***
A8 -0.080712 0.009819 -8.220 < 2e-16 ***
A9 0.007390 0.007105 1.040 0.298273
A10 0.041116 0.004085 10.065 < 2e-16 ***
A11 -0.041420 0.008418 -4.921 8.62e-07 ***
A12 -0.008241 0.007304 -1.128 0.259171
A13 -0.033161 0.008966 -3.699 0.000217 ***
A14 0.020818 0.005250 3.965 7.34e-05 ***
A15 -0.002995 0.006125 -0.489 0.624887
A16 -0.061997 0.017122 -3.621 0.000294 ***
A17 -0.025025 0.008391 -2.982 0.002860 **
---
Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
(Dispersion parameter for poisson family taken to be 1)
Null deviance: 1137.71 on 29 degrees of freedom
Residual deviance: 599.74 on 12 degrees of freedom
AIC: 840.1
Number of Fisher Scoring iterations: 5
>with(model1, cbind(res.deviance = deviance, df = df.residual,
p = pchisq(deviance, df.residual, lower.tail=FALSE)))
res.deviance df p
[1,] 599.7445 12 1.202013e-120
> require( pscl )
> Zip<-zeroinfl(model1,link="logit",dist="poisson")
**Error in zeroinfl(model1, link = "logit", dist = "poisson") :
invalid dependent variable, minimum count is not zero**
dput(尝试) 结构(列表(y = c)(156L,74L,221L,207L,168L,36L,128L, 208L,99L,117L,228L,211L,341L,173L,196L,310L,112L,203L, 104L,183L,325L,143L,218L,166L,218L,127L,136L,38L,102L, 34L),A1 = c(24L,24L,24L,19L,20L,9L,14L,23L,15L,23L, 14L,16L,15L,25L,25L,19L,24L,26L,25L,26L,22L,14L,13L, 15L,9L,12L,9L,12L,15L,18L),A2 = c(2L,4L,0L,3L,0L, 1L,1L,2L,1L,2L,0L,2L,2L,0L,1L,1L,3L,3L,2L,2L,3L, 2L,3L,5L,4L,3L,4L,1L,2L,1L),A3 = c(2L,2L,0L,1L,1L, 9L,3L,0L,0L,0L,1L,1L,3L,1L,0L,0L,1L,2L,3L,1L,0L, 1L,1L,0L,1L,1L,1L,0L,0L,2L),A4 = c(15L,11L,6L,7L, 10L,10L,5L,4L,5L,7L,9L,9L,4L,6L,6L,13L,9L,13L,9L, 10L,6L,6L,7L,6L,10L,9L,10L,7L,9L,2L),A5 = c(13L,10L, 6L,6L,11L,19L,13L,14L,7L,7L,6L,8L,10L,5L,7L,9L, 9L,11L,3L,13L,8L,8L,8L,6L,8L,9L,9L,14L,9L,6L),A6 = c(9L, 10L,9L,9L,4L,7L,7L,12L,11L,11L,12L,8L,6L,7L,8L, 5L,9L,6L,5L,6L,9L,11L,6L,6L,8L,9L,4L,11L,10L,7L ),A7 = c(21L,16L,13L,13L,4L,9L,12L,13L,12L,12L,12L, 6L,7L,6L,6L,4L,5L,9L,8L,7L,9L,12L,10L,7L,8L,12L, 14L,2L,6L,6L),A8 = c(1L,5L,10L,10L,1L,9L,6L,6L,7L, 7L,5L,6L,3L,2L,4L,0L,4L,2L,5L,5L,5L,3L,2L,4L,3L, 8L,10L,8L,2L,5L),A9 = c(8L,9L,10L,10L,12L,19L,10L, 6L,6L,6L,0L,6L,8L,10L,2L,3L,6L,2L,2L,6L,5L,2L, 4L,1L,3L,7L,7L,4L,4L,2L),A10 = c(7L,10L,12L,20L,24L, 21L,24L,18L,20L,18L,26L,21L,12L,11L,18L,18L,19L,16L, 25L,21L,22L,14L,12L,17L,21L,14L,14L,10L,8L,7L),A11 = c(0L, 2L,1L,4L,2L,1L,1L,1L,13L,10L,12L,5L,2L,0L,5L,1L, 4L,4L,3L,3L,1L,1L,3L,3L,5L,5L,2L,10L,3L,4L),A12 = c(12L, 14L,14L,17L,10L,14L,13L,19L,7L,5L,6L,6L,8L,7L,13L, 11L,10L,8L,6L,6L,9L,14L,9L,10L,8L,9L,8L,9L,5L,7L ),A13 = c(6L,2L,1L,5L,9L,6L,7L,4L,12L,5L,9L,10L, 3L,7L,4L,2L,2L,6L,4L,6L,7L,4L,9L,6L,11L,4L,5L, 4L,6L,6L),A14 = c(14L,13L,16L,11L,8L,6L,9L,13L,14L, 14L,9L,8L,12L,11L,13L,11L,18L,15L,20L,21L,17L,18L, 18L,18L,25L,20L,12L,9L,8L,8L),A15 = c(7L,6L,7L,5L, 4L,9L,12L,12L,11L,12L,9L,8L,7L,8L,10L,16L,8L,8L, 13L,10L,5L,5L,8L,10L,10L,4L,6L,6L,6L,7L),A16 = c(2L, 1L,3L,3L,1L,2L,3L,2L,3L,2L,2L,1L,2L,2L,3L,3L,2L, 1L,3L,4L,2L,5L,4L,8L,5L,2L,1L,2L,2L,2L),A17 = c(10L, 13L,13L,2L,5L,1L,3L,3L,5L,4L,4L,6L,4L,6L,3L,2L, 2L,2L,7L,8L,3L,7L,5L,6L,7L,6L,6L,3L,4L,3L))。。名称= c(“y”, “A1”,“A2”,“A3”,“A4”,“A5”,“A6”,“A7”,“A8”,“A9”,“A10”, “A11”,“A12”,“A13”,“A14”,“A15”,“A16”,“A17”),class =“data.frame”,row.names = c(NA, -30L))
以上是可重复的例子。对不起,我第一次在这里发帖,不太了解规则
答案 0 :(得分:1)
您的数据框在因变量$ y $:
中不包含零值分钟(MYDATA $ y)的 [1] 34
您需要至少有一个$ y = 0 $。