正确使用泰勒系列在给定的容差范围内

Question

我试图计算用户以弧度输入的角度的正弦函数。我还需要在给定的容差范围内打印该值。我花了很多时间，而且进展很少。任何帮助将不胜感激！谢谢！我的主要问题是返回给定容差范围内的值。

//容差是一个epsilon值 恩。 0.00001

public static void sineCalc(double angle, double tolerance) {
    int power = 1;
    double currentAnswer = 0.0;
    int count = 0;
    double answer = 0.0;
    double difference = 0.0;
    int i = 1;

    while (difference > tolerance ||  difference == 0) {

        if (i % 2 == 0) {
            currentAnswer = -Math.pow(angle, power) / getfactorial(power);
        } else {
            currentAnswer = Math.pow(angle, power) / getfactorial(power);
        }
        answer = answer + currentAnswer;
        power = power + 2;
        difference = Math.sin(angle) - answer;
        difference = Math.abs(difference);
        count++;
        i++;


    }

    System.out.println(answer);


}