矩形内外的坐标

Question

检查矩形内部或外部的x和y坐标 我有四个坐标NE，SW，NW，SE如果x和Y坐标在这个four_coordinates函数中相交为true，否则它应该是false 如果x和Y值不在这四个坐标内，它应该返回false但是我得到了真; 这个小提琴显示该函数当前返回true。

jsFiddle here https://jsfiddle.net/uwv249vc/

 function is_inside(point, loc) {
  var x_min = 12.306879896962968,
  x_max = 76.66268348693848,
  y_min = 12.297236015659891,
  y_max = 76.67736053466797


var  x =12.283985584345864,
y = 76.67015075683594;

var top_left = [x_min, y_min],
    top_right = [x_max, y_max],
    bottom_left = [x_max, y_min],
    bottom_right = [x_min, y_max];

console.log("top_left : " + top_left);
console.log("top_right : " + top_right);
console.log("bottom_left : " + bottom_left);
console.log("bottom_right : " + bottom_right);

var rectangle_value = [top_left, bottom_left, bottom_right, top_right];
console.log("rectangle_value" + rectangle_value);
for (var i = 0, j = rectangle_value.length - 1; i < rectangle_value.length; j = i++) {

    var xi = rectangle_value[i][0],
        yi = rectangle_value[i][1];

    var xj = rectangle_value[j][0],
        yj = rectangle_value[j][1];
    console.log("xi :" + xi + "yi :" + yi);
    console.log("xj :" + xj + "yj :" + yj);
    var intersect = ((yi > y) != (yj > y)) && (x < (xj - xi) * (y - yi) / (yj - yi) + xi);

    return intersect;
 }
}




console.log(is_inside())  //this must be false