向量<a> vs vector<a*> vs vector<shared_ptr<a> &gt; in C++

Question

I have a class A which is neither copy-constructable nor assignable. Now I want another class B to hold a vector of A objects. It is also clear that B holds the ownership of these objects.

As I see it, there are (at least) three options:

1. use vector<A>
2. use vector<A*>
3. use vector<shared_ptr<A> >

Is it right that 1. does not work because A is not copy constructable / assignable?

I don't like 2. because I have to make sure that I delete the pointers again.

If I use 3. I feel like this does not clearly represent that B is the owner of the A objects. Also I run into the issue that if I want users of B to delete pointers from this vector they need to pass the element they want to delete by shared_ptr<A>, right?

What would be a clean design decision in this case? Are there any good references on this?

Answer 1

1. 正确; A需要std::vector与unique_ptr一起使用，但是从C ++ 11开始，这很大程度上取决于您需要在向量上使用的操作。
2. 我同意，我不会再使用原始指针，除非我有一个非常令人信服的理由（在我看来这不是一个）。
3. 您考虑过{{1}}了吗？这个选项有一个很好的copy-assignable and copy-constructible。