stat以填充通过引用

时间:2016-01-11 08:55:04

标签: c++ linux stat

我有一个函数,它通过引用接受struct并填充其中的文件的细节,但是当我编译时,我得到以下错误:

error: no matching function for call to ‘stat::stat(char*&, stat*)’
         stat (buffer,&buf);

有人可以让我知道如何将缓冲区传递给stat?

以下是代码:

void filedetails(char *path, int pathlen ,struct stat &buf){
        char *buffer;
        strncpy(buffer,path,pathlen-1);
        buffer[pathlen-1]='\0';
        stat (buffer,&buf);
}

它被称为如下:

struct stat st_buf;
char path[256];
//path gets filled here and is manually null terminated//
path[256] = '\0';
filedetails(path,256,st_buf);

0 个答案:

没有答案