Question

我想写一个程序，询问用户一个单词，只返回常量。但是我坚持使用这个程序，我希望这个程序可以做我上面提到的，但它所做的就是逐行返回这个单词。

original = input('Enter a word:')
word = original.lower()
first = word[0]
second = word[1]
third = word[2]
fourth = word[3]
fifth=word[4]


if first == "a" or "e" or "i" or "u":
    print (first)
else:
    print ("")
if second == "a" or "e" or "i" or "u":
    print (second)
else:
    print ("")
if third == "a" or "e" or "i" or "u":
    print (third)
else:
    print ("")
if fourth == "a" or "e" or "i" or "u":
    print (fourth)
else:
    print ("")
if fifth == "a" or "e" or "i" or "u":
    print (fifth)
else:
    print ("")

Answer 1

从单词中删除所有元音并打印出来：

original = input('Enter a word:')
print("".join(x for x in original if x.lower() not in "aeiou"))

Answer 2

优先权是错误的。＆＃34;或＆＃34;优先级高于＆＃34; ==＆＃34; - 见https://docs.python.org/2/reference/expressions.html#operator-precedence

所以这一行：

if first == "a" or "e" or "i" or "u":

与：

相同

if (first == "a") or ("e") or ("i") or ("u"):

我怀疑它不是你想要的。以下可能会更好：

if first in "aeiu":

但是也要注意这是区分大小写的......

是否有一个程序只返回单词python中的常量

2 个答案: