Question

如果城市在我的list_cities中，我想在我的地址栏中返回城市。

Cities = ['Los Angeles','New York']
Address = ['New York 123 ave unit 804','Los Angeles 567 ave unit 701']

if any(city in address for city in Cities):
    print ()

我想要回归['纽约'，'洛杉矶']，有什么方法可以做到这一点吗？谢谢！

Answer 1

您可以代替Cities进行迭代：

Cities = ['Los Angeles','New York']
Address = ['New York 123 ave unit 804','Los Angeles 567 ave unit 701']
final_cities = [i for i in Cities if any(i in b for b in Address)]

根据Address中的位置排序的解决方案：

new_Address = {a:[c for c, d in enumerate(Address) if a in d] for a in Cities}
final_address = map(lambda x:x[0], sorted({a:b for a, b in new_Address.items() if b}.items(), key=lambda x:x[-1]))

输出：

['New York', 'Los Angeles']

如果单词在列表字符串中，则返回单词

1 个答案: