我在下面写了以下代码。它的工作没有错误，我面临的问题是，如果一个句子中有2个单词重复相同的次数，则代码不会按字母顺序返回第一个单词。任何人都可以建议任何替代品？这段代码将在Python 2.7中进行评估。
"""Quiz: Most Frequent Word"""
def most_frequent(s):
"""Return the most frequently occuring word in s."""
""" Step 1 - The following assumptions have been made:
- Space is the default delimiter
- There are no other punctuation marks that need removing
- Convert all letters into lower case"""
word_list_array = s.split()
"""Step 2 - sort the list alphabetically"""
word_sort = sorted(word_list_array, key=str.lower)
"""Step 3 - count the number of times word has been repeated in the word_sort array.
create another array containing the word and the frequency in which it is repeated"""
wordfreq = []
freq_wordsort = []
for w in word_sort:
wordfreq.append(word_sort.count(w))
freq_wordsort = zip(wordfreq, word_sort)
"""Step 4 - output the array having the maximum first index variable and output the word in that array"""
max_word = max(freq_wordsort)
word = max_word[-1]
result = word
return result
def test_run():
"""Test most_frequent() with some inputs."""
print most_frequent("london bridge is falling down falling down falling down london bridge is falling down my fair lady") # output: 'bridge'
print most_frequent("betty bought a bit of butter but the butter was bitter") # output: 'butter'
if __name__ == '__main__':
test_run()
答案 0 :(得分：0)
如果不对代码进行过多处理，我发现通过使用index方法可以实现一个好的解决方案。
找到频率最高的字（ max_word ）后，只需在 wordfreq 上调用index方法即可 max_word 作为输入，返回其在列表中的位置;然后在 word_sort 中返回与此索引关联的单词。
代码示例如下（我删除了zip函数，因为它不再需要了，并添加了两个更简单的示例）：
"""Quiz: Most Frequent Word"""
def most_frequent(s):
"""Return the most frequently occuring word in s."""
""" Step 1 - The following assumptions have been made:
- Space is the default delimiter
- There are no other punctuation marks that need removing
- Convert all letters into lower case"""
word_list_array = s.split()
"""Step 2 - sort the list alphabetically"""
word_sort = sorted(word_list_array, key=str.lower)
"""Step 3 - count the number of times word has been repeated in the word_sort array.
create another array containing the word and the frequency in which it is repeated"""
wordfreq = []
# freq_wordsort = []
for w in word_sort:
wordfreq.append(word_sort.count(w))
# freq_wordsort = zip(wordfreq, word_sort)
"""Step 4 - output the array having the maximum first index variable and output the word in that array"""
max_word = max(wordfreq)
word = word_sort[wordfreq.index(max_word)] # <--- solution!
result = word
return result
def test_run():
"""Test most_frequent() with some inputs."""
print(most_frequent("london bridge is falling down falling down falling down london bridge is falling down my fair lady")) # output: 'down'
print(most_frequent("betty bought a bit of butter but the butter was bitter")) # output: 'butter'
print(most_frequent("a a a a b b b b")) #output: 'a'
print(most_frequent("z z j j z j z j")) #output: 'j'
if __name__ == '__main__':
test_run()