Question

第一个函数计算字符串的字符

def character_count(sentence):
    characters = {}
    for char in sentence:
        if char in characters:
            characters[char] = characters[char] + 1
        else: 
            characters[char] = 1
    return characters

第二个函数确定最常见的字符，并通过在前一个辅助函数中建立的字符[char]来识别哪个字符最常出现

def most_common_character(sentence):
    chars = character_count(sentence)
    most_common = ""
    max_times = 0


    for curr_char in chars:
        if chars[curr_char] > max_times:
            most_common = curr_char
            max_times = chars[curr_char]
    return most_common

Answer 1

为什么不简单地使用Python提供的内容？

>>> from collections import Counter
>>> sentence = "This is such a beautiful day, isn't it"
>>> c = Counter(sentence).most_common(3)
>>> c
[(' ', 7), ('i', 5), ('s', 4)]

如果你真的想逐字逐句地避开空格：

>>> from collections import Counter
>>> sentence = "This is such a beautiful day, isn't it"
>>> res = Counter(sentence.replace(' ', ''))
>>> res.most_common(1)
[('i', 5)]

Answer 2

你实际上不需要改变任何东西！您的代码将按原样使用列表（变量名称只会变得误导）。试试吧：

most_common_character(['this', 'is', 'a', 'a', 'list'])

输出：

'a'

这适用于包含任何可清洗元素（数字，字符串，字符等）的列表

给定输入为“句子”，如何返回最多出现的元素

2 个答案: