Question

我有以下sql查询：

SELECT
a.url,
b.lpvs,
a.volume,
a.sales_usd,
a.sales_eur,
a.sales_gbp,
a.sales_jpy
FROM (
SELECT
referer_trackings.cookie_first_url AS url,
count(purchases.id) AS volume,
SUM(CASE WHEN purchases.currency = 'USD' THEN purchases.price ELSE 0 END) AS sales_usd,
SUM(CASE WHEN purchases.currency = 'EUR' THEN purchases.price ELSE 0 END) AS sales_eur,
SUM(CASE WHEN purchases.currency = 'GBP' THEN purchases.price ELSE 0 END) AS sales_gbp,
SUM(CASE WHEN purchases.currency = 'JPY' THEN purchases.price ELSE 0 END) AS sales_jpy
FROM purchases
JOIN referer_trackings 
ON referer_trackings.trackable_id = purchases.id
JOIN items
ON purchases.item_id = items.id
WHERE items.seller_id = '6'
AND referer_trackings.trackable_type = 'Purchase'
AND purchases.workflow_state = 'payment_successful'
GROUP BY referer_trackings.cookie_first_url
ORDER BY volume DESC
) AS a, (SELECT
count(referer_trackings.id) AS lpvs
FROM referer_trackings
JOIN product_landing_page_views
ON product_landing_page_views.id = referer_trackings.trackable_id
JOIN items
ON items.id = product_landing_page_views.item_id
WHERE referer_trackings.trackable_type = 'ProductLandingPageView'
AND items.seller_id = '6')
AS b

这产生了这个结果：

url    lpvs    volume    sales_usd    sales_eur   sales_gbp   sales_jpy
=======================================================================

url1   1082    3         9.99         9.99        9.99        0.0
url2   1082    1         0.0          9.99        0.0         0.0
        ^

lpvs列的第二行（值：1082，下面带有小箭头）应为0，而不是1082.值1082仅对第一行正确。

我知道这是因为加入/选择时加倍了但我似乎无法解决这个问题并使查询恰到好处。

我可以从我的ruby代码中调用两个查询并合并结果。这将是快速解决方案。但是，我想保持这个清洁，并寻求一个纯粹的SQL解决方案。我觉得我非常接近。

如果有人知道如何使用ActiveRecord做到这一点，那也很好： - ）。

谢谢你的时间！

=====编辑=====

基于Rahul的调整，这是查询的结果：

url    lpvs    volume    sales_usd    sales_eur   sales_gbp   sales_jpy
=======================================================================

url1   7       7         19.98        29.97       19.98       0.0
url2   1       1         0.0          9.99        0.0         0.0
       ^       ^         ^            ^           ^

^1, row 1 => value should be 1082
^1, row 2 => value should be 0
^2, row 1 => value should be 3
^2, row 2 => value should be 1
^3, row 1 => value should be 9.99 (current value is doubled somehow)
^4, row 1 => value should be 9.99 (current value is tripled somehow)
^5, row 1 => value should be 9.99 (current value is doubled somehow)

Answer 1

那是因为你在查询部分下面的虚假信息，我不知道你为什么这么做......

fread()

在您的主要选择中，您正在说

....
ORDER BY volume DESC
) AS a, (SELECT
count(referer_trackings.id) AS lpvs
FROM referer_trackings
........)
AS b

是的，将整个查询修改为如下所示

SELECT
a.url,
b.lpvs, <-- result of above posted query part

sql在双选查询中产生双值

1 个答案: