Question

我有两个查询。一个将得出特定过程类型的记录总数。另一个按物种产生该特定过程的记录数

我试图弄清楚如何获取每种特定过程类型的计数和平均数。

按过程类型查询产生总数：

/* The following query will show the total number of studies by imaging area. */
SELECT 
    PlacerFld2 AS "Type of Procedure", Count(*) AS "Count of Procedures"
FROM 
    [order] o
WHERE 
    lastmodifieddate BETWEEN '2017-01-01 00:00:00' AND '2017-12-31 23:59:59'
    AND SiteBridgeID = '1' /* Medical Imaging */
    AND OrderStatusID <> '4'
    AND placerfld2 IN ('CARD', 'CARM', 'CRFL', 'CT', 'I131', 'LACR', 'LAUS', 'NUCMED','OUTFM','PCCR','PETCT','PETR','PHMR','SACR','SAES','SAMR','SAUS','VRC','VRUS')
GROUP BY 
    PlacerFld2
ORDER BY 
    PlacerFld2 ASC

示例输出：

CT    2056
SAMR  1800
SACR  3600

查询按物种产生的程序总数

/* The following query will break down the number of studies by species */
SELECT PlacerFld2 AS "Type of Procedure", City AS Species, Count(*) AS "Count of Procedures"
FROM [order] o

LEFT JOIN Visit v
ON o.VisitID = v.VisitID

LEFT JOIN PatientInfo pif
ON v.PatientID = pif.PatientID

LEFT JOIN Patient p
ON pif.PatientID = p.PatientID

LEFT JOIN PersonalInfo perinfo
ON p.PersonalInfoID = perinfo.PersonalInfoID

WHERE o.lastmodifieddate between '2017-01-01 00:00:00' AND '2017-12-31 23:59:59'
AND SiteBridgeID = '1' /* Medical Imaging */
AND OrderStatusID <> '4'
AND placerfld2 IN ('CARD','CARM','CRFL','CT','I131','LACR','LAUS','NUCMED','OUTFM','PCCR','PETCT','PETR','PHMR','SACR','SAES','SAMR','SAUS','VRC','VRUS')

GROUP BY Placerfld2, CITY
ORDER BY placerfld2 ASC, CITY ASC

示例表输出：

CT    CANINE   1500
CT    FELINE   556
SAMR  CANINE   1000
SAMR  FELINE   600
SAMR  EQUINE   200

所需结果：

CT    CANINE   1500   72.9%
CT    FELINE   556    27.1%
SAMR  CANINE   1000   55.5%
SAMR  FELINE   600    33.3%
SAMR  EQUINE   200    11.1%

Answer 1

您可以使用窗口功能：

class Child1
{
    void mustDefine() { ... }
};

class Child2
{
    void mustDefine() { ... }
};

class NotChild
{
};

template<typename T>
void usesMustDefine(T t)
{
    t.mustDefine();
}

int main()
{
    Child1 c1;
    Child2 c2;
    NotChild c3;

    usesMustDefine(c1); // Succeeds
    usesMustDefine(c2); // Succeeds
    // usesMustDefine(c3); // Fails

    c1.mustDefine(); // Succeeds
    c2.mustDefine(); // Succeeds
    // c3.mustDefine(); // Fails

    return 0;
}

Answer 2

如果公用表表达式不是您的选择（因为它们不受支持，或者您只是不喜欢它们），则可以通过子查询来做到这一点：

/* The following query will break down the number of studies by species */
SELECT PlacerFld2 AS "Type of Procedure", City AS Species, Count(*) AS "Count of Procedures", COUNT(*) / x.[Count of Procedures] AS "Percentage"
FROM [order] o

LEFT JOIN Visit v
ON o.VisitID = v.VisitID

LEFT JOIN PatientInfo pif
ON v.PatientID = pif.PatientID

LEFT JOIN Patient p
ON pif.PatientID = p.PatientID

LEFT JOIN PersonalInfo perinfo
ON p.PersonalInfoID = perinfo.PersonalInfoID

LEFT JOIN (
    /* The following query will show the total number of studies by imaging area. */
    SELECT 
        PlacerFld2 AS "Type of Procedure", Count(*) AS "Count of Procedures"
    FROM 
        [order] o
    WHERE 
        lastmodifieddate BETWEEN '2017-01-01 00:00:00' AND '2017-12-31 23:59:59'
        AND SiteBridgeID = '1' /* Medical Imaging */
        AND OrderStatusID <> '4'
        AND placerfld2 IN ('CARD', 'CARM', 'CRFL', 'CT', 'I131', 'LACR', 'LAUS', 'NUCMED','OUTFM','PCCR','PETCT','PETR','PHMR','SACR','SAES','SAMR','SAUS','VRC','VRUS')
    GROUP BY 
        PlacerFld2) x ON x.[Type of Procedure] = PlacerFld2
--ORDER BY 
--    PlacerFld2 ASC

WHERE o.lastmodifieddate between '2017-01-01 00:00:00' AND '2017-12-31 23:59:59'
AND SiteBridgeID = '1' /* Medical Imaging */
AND OrderStatusID <> '4'
AND placerfld2 IN ('CARD','CARM','CRFL','CT','I131','LACR','LAUS','NUCMED','OUTFM','PCCR','PETCT','PETR','PHMR','SACR','SAES','SAMR','SAUS','VRC','VRUS')

GROUP BY Placerfld2, CITY, x.[Count of Procedures]
ORDER BY placerfld2 ASC, CITY ASC

这里的基本模式是：

SELECT... <your detail query>
FROM
    <your original detail tables>
    LEFT JOIN (<your summary query>) x ON x.<a field> = <original field>
WHERE.... <the rest of your detail query>
GROUP BY... <remember to add the new summary total to the GROUP BY clause>

SQL查询产生次数和平均值

2 个答案: