伙计们,我拼命地知道如何将EntityManager.getReference与多于一个主键一起使用,因为当我想要更新数据时总是会出错, 错误消息类似:
[EL Fine]:sql:Connection(1713950866) - SELECT Category,SubCategory,Code,CreatedBy,CreatedDateTime,IsActive,Remarks,UpdatedBy,UpdatedDateTime,Value FROM master.sysParameter WHERE(((Category =?)AND( SubCategory =?))AND(Code =?)) bind => [acm,acm,acm] javax.persistence.EntityNotFoundException:找不到id:acm的实体 在org.eclipse.persistence.internal.jpa.EntityManagerImpl.getReference(EntityManagerImpl.java:1398)
在我的代码中我想定义3个变量,但我只得到1(acm)。 这是我的代码示例:
public boolean updateSysParameter(MasterSysParameterEntity masterSysParameter) {
// TODO Auto-generated method stub
boolean retVal = false;
try{
MasterSysParameterEntity updateSysParameter;
em = getEntityManagerFactory();
em.getTransaction().begin();
System.out.println("masterSysParameter.getCategory() => " +masterSysParameter.getCategory());
updateSysParameter = em.getReference(MasterSysParameterEntity.class, masterSysParameter.getCategory());
updateSysParameter = em.getReference(MasterSysParameterEntity.class, masterSysParameter.getSubCategory());
updateSysParameter = em.getReference(MasterSysParameterEntity.class, masterSysParameter.getCode());
updateSysParameter = em.merge(masterSysParameter);
em.getTransaction().commit();
retVal = true;
}catch (Exception e) {
if(em != null && null != em.getTransaction())
em.getTransaction().rollback();
e.printStackTrace();
} finally {
if (em != null) {
em.close();
}
}
return retVal;
}
非常感谢任何建议和帮助,这真的意味着很多
答案 0 :(得分:2)
如果实体中有多个@Id
字段,那么您可以定义@IdClass
on the entity for the composite id。所以你调用em.getReference
传递第二个参数作为" IdClass"的实例。
MyIdClass myId = new MyIdClass(...); // Pass in whatever args your IdClass needs
MyEntity ent = em.getReference(MyEntity.class, myId);