Question

我想从我的数据库中回显多于1个id，如何在索引页面中显示多个id？

我的功能：

function query($sql) {
 global $conn;
 $results = mysql_query($sql, $conn);
 $rows = array();
 if(!is_bool($results))
     while($row = mysql_fetch_assoc($results)) 
         $rows['id'] = $row;
    return $rows;
}

我的索引页面：

<?php foreach($funds as $fund) { ?>

 <td width="87%" valign="top"><ul id="funds" class="bodycopy2" style="margin:0;">
  <li><?php echo $fund['fund']; ?><span class="price"><div align="center" class="h1"><strong><br />R123.45</strong> <br />as at <br />1 January 2012</div></span></li>
  <li><?php echo $fund['fund']; ?><span class="price"><div align="center"   class="h1">  <strong><br />R200.45</strong> <br />as at <br />1 January 2012</div></span>   </li>
  <li><?php echo $fund['fund']; ?><span class="price"><div align="center" class="h1">   <strong><br />R150.00</strong> <br />as at <br />1 January 2012</div></span></li>
 </td>
     </tr>

     </table>
    <?php } ?>

Answer 1

你可以使用一组id：

$rows['ids'][] = $row;

然后你可以使用

来查看ID

foreach ($rows as $id)

如果您只保留身份证，请直接$rows[] = $row。

Answer 2

您始终会覆盖相同的元素$rows['id'] = $row;。你应该做

$rows['id'][] = $row;

显示你应该在$ rows上重复的id

foreach($rows['id'] as $id){
    echo $id;
}

回响超过1个id

2 个答案: