Question

所以，我制作的游戏选择一个随机数，你必须猜测它是什么，但是，当它说你赢了或者你丢失了文本只是留在那里我可以＆＃39;弄清楚如何删除旧文本。我试过做screen.blit（背景，（0,0）），但它并没有改变一件事。（是的，我确实做了pygame.display.flip（））我已经浏览了整个网络（我先查看了堆栈溢出），但没有成功。帮助！

import random, pygame, pygbutton
from pygame.locals import *

pygame.init()
dice = random.randint(1, 6)

def window():
    width = 600
    height = 600
    # background_color = (0, 0, 0)
    WH = (width, height)
    screen = pygame.display.set_mode(WH)
    background = pygame.image.load("wood.jpg").convert()
    background=pygame.transform.scale(background,(600, 600))
    pygame.display.set_caption("Dice Game!")
    screen.blit(background, (600, 600))
    num1_button = pygbutton.PygButton((0, 0, 100,50), '1')
    num2_button = pygbutton.PygButton((0, 50, 100, 50), '2')
    # screen.fill(background_color)
    font = pygame.font.Font(None, 100)

    running = True
    while running == True:
        dice = random.randint(1, 6)
        screen.blit(background, (0, 0))

        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                running = False
            if event.type == KEYDOWN:
                if event.key == pygame.K_ESCAPE:
                    quit()
            if 'click' in num1_button.handleEvent(event):
                if dice == 1:
                    text = font.render("You Win!", 1, (0, 0, 0))
                    background.blit(text, (155, 255))
                    screen.blit(background, (0, 0))
                else:
                    Text = font.render("You Lose!", 1, (0, 0, 0))
                    background.blit(Text, (155, 255))
                    screen.blit(background, (0, 0))
                cliq = True
            if 'click' in num2_button.handleEvent(event):
                if dice == 2:
                    text = font.render("You Win!", 1, (0, 0, 0))
                    background.blit(text, (155, 255))
                    screen.blit(background, (0, 0))
                else:
                    Text = font.render("You Lose!", 1, (0, 0, 0))
                    background.blit(Text, (155, 255))
                    screen.blit(background, (0, 0))
                cliq=True

        num1_button.draw(screen)
        num2_button.draw(screen)
        pygame.display.flip()   


window()

如果你告诉我把改变放在哪里，我也会喜欢它。谢谢你提前！

Answer 1

您的问题是您将文本blitting到背景表面。这个文字一直存在，直到你重新加载表面。重新加载表面是一个坏主意。这需要大量的cpu功能，你不需要花费。相反，只需将文本直接插入屏幕即可。

        if 'click' in num1_button.handleEvent(event):
            if dice == 1:
                text = font.render("You Win!", 1, (0, 0, 0))
                screen.blit(text, (155, 255))

Pygame文本重叠

1 个答案: