这里是tv_1
表:
id | fig
-------------
111 | 500
222 | 200
111 | 300
111 | 200
111 | 300
此处tv_2
:
id | test
-------------
111 | 50
111 | 70
111 | 40
当我执行此查询时:
SELECT sum(tv_1.fig), tv_2.id
FROM tv_1
JOIN tv_2 ON tv_1.id = tv_2.id
WHERE tv_1.id = 111
GROUP BY tv_2.id
我明白了:
sum | id
-------------
3900 | 111
但我需要得到:
sum | id
-------------
1300 | 111
我该怎么做?
答案 0 :(得分:0)
找到了答案!
SELECT SUM(tv_1.fig), v.id
FROM tv_1
INNER JOIN (SELECT DISTINCT tv_2.id FROM tv_2) v ON v.id = tv_1.id
WHERE tv_1.id = 111
GROUP BY v.id
这给了我:
sum | id
-------------
1300 | 111