行数乘以结果数

Question

SELECT  s.SR_Service_RecID    -- will have 1 result
     ,  p.Description         -- will have 8 results 
     ,  t.notes               -- will have 5 results

FROM SR_Service s
     LEFT JOIN IV_Product p
            ON p.SR_Service_RecID = s.SR_Service_RecID
     LEFT JOIN Time_Entry t
            ON t.SR_Service_RecID = s.SR_Service_RecID

此查询将p.Description乘以t.Notes以获取总行数。每个p.Description对每个个体t.notes显示5次。

结果集：

SR_RecID    Description    Notes
12345       Product 1      Note 1
12345       Product 1      Note 2
12345       Product 1      Note 3
12345       Product 1      Note 4
12345       Product 1      Note 5
12345       Product 2      Note 1
12345       Product 2      Note 2
12345       Product 2      Note 3
12345       Product 2      Note 4
12345       Product 2      Note 5
Etc..

我不确定如何解决这个......任何帮助都会受到赞赏。

[编辑]： 由于结果是正确的，您如何将其放入SSRS报告中以仅显示正确的结果数量，因为它将显示所有重复的行？

SR_RecID
12345

Description
Product 1
Product 2
Product 3
Product 4
Product 5
Product 6
Product 7
Product 8

Notes 1
Notes 2
Notes 3
Notes 4
Notes 5

Answer 1

如果通过“解析”表示如何只为每个SR_RecID和Description添加1个音符，那么您需要使用聚合函数（{{{{{{ {1}}，Notes等）。

否则，多次评论，您的结果是预期的结果。