Question

char* matrix [10][10];  //matrix to put words in (all elements are equal to 1 at this point)
char words[20][20]= {
    " c a t "," c a r "," b e a r ",
    " s h i p "," m o u s e "," b e a t l e ",
    " c o a t "," n e s t "," i c e "," s u g a r ",
    " b a c o n "," f r o w n "," s m i l e "," d e a d ",
    " f e a t h e r "," g o a t "," h e n "," j e l l y ",
    " k o a l a "," l i p s "
}; // 4 of these words will be randomly chosen

for( i=0;i<4;i++){
    d=0;
    do{
        random = (rand()%20);
        list[i]=words[random];
        d=0;
        for( j=0;j<i;j++){
            if(strcmp(words[random],list[j])==0)d=1;
        }
    }while(d);//making sure there are no duplicate words

    strcpy(temp, words[random] );
    length=strlen(temp); //length of word
    printf("temp:%s",words[random]);
    ans=(length/2);// length divided by 2 to remove spaces
    size=(9-ans);// number of columns-word length

    emptyD=0;   
    do{
        x=(rand()%10);//generates a random co-ordinate
        emptyD=0;
        for(k=0;k<ans;k++){// for loop starting from zero till the length of word
            if(strcmp(matrix[x+k][x+k],"1")==0)
             emptyD=1; //checks whether the matrix element is equal to 1 
        }
    } while(emptyD || x>size);
}

基本上我在这里要做的就是用文字填充矩阵对角放置。为了避免与我设置整体的其他单词发生冲突矩阵到1预先。每次一个角色进入该程序检查元素空间是否等于1（表示它是空的正）。但是这段代码工作不正常，仍然存在碰撞。我将不胜感激任何帮助:)谢谢

Answer 1

由于分配给ans和size的值，您可能面临的所有可能性。我相信matrix[10][10]是造成问题的原因，因为对于x=9和任何k>1，您最终会访问数组边界。

您可能希望在比较后break for(k=0;k<ans;k++)循环并指定emptyD=1;。但肯定需要检查访问数组索引。

或类似的东西应该有帮助

//no  for loop required
if(strcmp(matrix[x][x],"1")==0) {
  emptyD=1; //checks whether the matrix element is equal to 1 
}

我不知道什么会结束while循环，因为你知道这些值更好并且它们经过测试：）

碰撞检查不起作用

1 个答案: