压缩两个列表并加入它们的元素

Question

我想加入此列表：

list1 = [1, 2, 3]
list2 = ['a', 'b', 'c']
merged = ['1a', '2b', '3c']

list1和list2的大小始终相同。

Answer 1

这适用于你提到过的案例：

list1 = [1, 2, 3]
list2 = ['a', 'b', 'c']
list3 = [str(x[0]) + x[1] for x in zip(list1, list2)]

Answer 2

这是解决方案

list1=[1, 2, 3]  
list2=['a', 'b', 'c']

[str(list1[i])+list2[i] for i in xrange(len(list1))]

这将输出：['1a', '2b', '3c']

Answer 3

我更喜欢：

>>> list1 = [1, 2, 3]
>>> list2 = ['a', 'b', 'c']
>>> [''.join(map(str, i)) for i in zip(list1, list2)]
['1a', '2b', '3c']
>>> 

Answer 4

map(lambda x,y: str(x)+y,list1,list2) 

这将输出：['1a', '2b', '3c']

Answer 5

我更喜欢：

>>> list1 = [1, 2, 3]
>>> list2 = ['a', 'b', 'c']
>>> [str(i) + str(j) for i, j in zip(list1, list2)]
['1a', '2b', '3c']

Answer 6

你可以在功能上做到：

list1 = [1, 2, 3]
list2 = ['a', 'b', 'c']
merged = ['1a', '2b', '3c']


print(list(map("".join, zip(map(str,list1), list2))))
['1a', '2b', '3c']