Python zip()两个列表

时间:2016-05-02 02:19:02

标签: python python-3.x zip

我试图压缩两个长度相同的列表,但我总是得到错误 " zip对象位于0x0000000002A81548"而不是压缩列表。

filename = input("Which file do you want to open?: \n")

file = open("C:/"+ filename,'r')


movielist = []
moviename = []
moviedate = []

for line in file:  
    line.strip()  
    name = re.search('name:(.*)',line)
    date = re.search('date:(.*)',line)

    if name:
        titel = name.group(1)
        moviename.append(titel)
    if date:
        datum = date.group(1)
        moviedate.append(datum)

print("Name of the list: ", moviename.pop(0))

movielist= zip(moviename,moviedate)

print(movielist)

print("Number of movies: " , len(moviename))

1 个答案:

答案 0 :(得分:4)

movielist= list(zip(moviename,moviedate))

在Python 2 zip中返回一个列表,不需要上面的内容。在Python 3中,它返回一个特殊的惰性zip对象,类似于生成器或itertools.izip,您需要具体使用lenmap也是如此。