Question

public class Person()
    {
    int ID;
    string Name;
    DateTime ChangeDate
    } 



var list1 = new List<Person>
    {
        new Person { ID= 1, Name = "Peter", ChangeDate= "2011-10-21" },
        new Person { ID= 2, Name = "John",  ChangeDate= "2011-10-22" },
        new Person { ID= 3, Name = "Mike",  ChangeDate= "2011-10-23" },
        new Person { ID= 4, Name = "Dave",  ChangeDate= "2011-10-24" }
    };

 var list2 = new List<Person>
    {
        new Person { ID= 1, Name = "Pete",  ChangeDate= "2011-10-21" },
        new Person { ID= 2, Name = "Johny", ChangeDate= "2011-10-20" },
        new Person { ID= 3, Name = "Mikey", ChangeDate= "2011-10-24" },
        new Person { ID= 5, Name = "Larry", ChangeDate= "2011-10-27" }
    };

作为输出，我想有list1 + list2 =

    Person { ID= 1, Name = "Peter", ChangeDate= "2011-10-21" },
    Person { ID= 2, Name = "John",  ChangeDate= "2011-10-22" },
    Person { ID= 3, Name = "Mikey", ChangeDate= "2011-10-24" },
    Person { ID= 4, Name = "Dave",  ChangeDate= "2011-10-24" }
    Person { ID= 5, Name = "Larry", ChangeDate= "2011-10-27" }

算法是这样的。加入两个清单。如果列表的元素具有相同的ID，请通过ChangeDate进行比较，并使用更大的日期。如果ChangeDate是equeal采取其中任何一个，但不是两个。也许它更容易连接两个列表，而不是用lambda过滤它们。我试过了，但总是拿出一些丑陋的代码：/

有人有任何想法吗？

Answer 1

LINQ

var q = from person in list1.Concat(list2)
        group person by person.ID into g
        select g.OrderByDescending(p => p.ChangeDate).First();

Answer 2

合并两个列表在降序日期排序。现在您需要在排序列表中首先出现每个id。

Answer 3

这样的事情怎么样？

using System;
using System.Collections.Generic;
using System.Linq;

public class Person
{
    public int ID;
    public string Name;
    public DateTime ChangeDate;
}

public class PersonComparer : IEqualityComparer<Person>
{
    public bool Equals(Person p1, Person p2)
    {
        return p1.ID == p2.ID;
    }

    public int GetHashCode(Person p)
    {
        return p.ID.GetHashCode();
    }
}

class Program
{
    static void Main(string[] args)
    {
        var list1 = new List<Person>
        {
            new Person { ID = 1, Name = "Peter", ChangeDate = DateTime.Parse("2011-10-21") },
            new Person { ID = 2, Name = "John",  ChangeDate = DateTime.Parse("2011-10-22") },
            new Person { ID = 3, Name = "Mike",  ChangeDate = DateTime.Parse("2011-10-23") },
            new Person { ID = 4, Name = "Dave",  ChangeDate = DateTime.Parse("2011-10-24") }
        };

        var list2 = new List<Person>
        {
            new Person { ID = 1, Name = "Pete",  ChangeDate = DateTime.Parse("2011-10-21") },
            new Person { ID = 2, Name = "Johny", ChangeDate = DateTime.Parse("2011-10-20") },
            new Person { ID = 3, Name = "Mikey", ChangeDate = DateTime.Parse("2011-10-24") },
            new Person { ID = 5, Name = "Larry", ChangeDate = DateTime.Parse("2011-10-27") }
        };

        var pc = new PersonComparer();
        var combined = list1.Join(list2, p => p.ID, p => p.ID, (p1,p2) => p2.ChangeDate > p1.ChangeDate ? p2 : p1)
                            .Union(list1.Except(list2, pc))
                            .Union(list2.Except(list1, pc));

        foreach(var p in combined)
        {
            Console.WriteLine(p.ID + " " + p.Name + " " + p.ChangeDate);
        }
    }
}

Answer 4

您可以连接并对它们进行排序，然后获得不同的值：

class PersonIdEqualityComparer : IEqualityComparer<Person>
{
    public bool Equals(Person x, Person y)
    {
        return x.ID == y.ID;
    }

    public int GetHashCode(Person person)
    {
        return person.ID;
    }
}

var result = list1.Concat(list2)
    .OrderByDescending(i => DateTime.Parse(i.ChangeDate)) // Most recent first
    .Distinct(new PersonIdEqualityComparer())
    ;

这假设Distinct将获取每个集合中遇到的第一个项目而不是任意项目。考虑到它可能只是在遍历集合时将它们插入HashSet，这对我来说似乎是合理的。

它也没有错误检查。如果任何值可能为null，或者ChangeDate可能无效，则此代码将抛出异常。如果这可能是个问题，我建议您在传入之前检查数据，并在PersonIdEqualityComparer类中进行错误检查。

加入两个列表比较它们的元素属性

4 个答案: