现在我正在制作一个程序,打印出学生姓名,身份证号码,考试成绩,平均分数和成绩。由于某些原因,计算平均分数的方法存在问题。我试过添加括号,但也没有改变结果。这最终会影响成绩,因为成绩是用平均分来计算的。任何帮助表示赞赏,谢谢!这是我的代码:
import java.util.Scanner;
public class Student {
private String fname;
private String lname;
private int id;
private int score1;
private int score2;
private int score3;
private double average;
private String grade;
public void readInfo()
{
Scanner k = null;
k = new Scanner (System.in);
System.out.println ("Please enter the first name: (Enter John as first name and Doe as last name to stop) ");
fname = k.next();
System.out.println("Please enter the last name: ");
lname = k.next();
if (fname.equalsIgnoreCase("John")&&lname.equalsIgnoreCase("Doe"))
System.exit(0);
System.out.println("Please enter the student ID: ");
id = k.nextInt();
System.out.println("Please enter the first score: ");
score1 = k.nextInt();
System.out.println("Please enter the second score: ");
score2 = k.nextInt();
System.out.println("Please enter the third score: ");
score3 = k.nextInt();
}
//The problem lies in here:
private void computeAverage()
{
average = score1+score2+score3/3.0;
}
private void computeGrade()
{
if (average>=90&&average<=100)
grade = "A";
else if (average>=80&&average<=89.9)
grade = "B";
else if (average>=70&&average<=79.9)
grade = "C";
else if (average>=60&&average<=69.9)
grade = "D";
else
grade = "F";
}
private String getName()
{
return fname + " " + lname;
}
private double getAverage()
{
return average;
}
public void printAll()
{
System.out.printf("%-9s%-10s %-9s %-3s %-3s %-3s %-5s %-5s", "LastName","FirstName","ID","S1","S2","S3","AVG","GRADE");
System.out.println();
System.out.println("-----------------------------------------------------");
System.out.printf("%-9s%-9s %-9d %-3d %-3d %-3d %-3.2f%-2s",lname,fname,id,score1,score2,score3,average,grade);
System.out.println();
System.out.println("-----------------------------------------------------");
}
}
答案 0 :(得分:1)
答案 1 :(得分:0)
操作顺序。你正在做的是sum 1 + sum 2
加上 sum3和3的商。当你除以时,你必须除以完全你需要分割的东西。你应该做(sum 1+ sum 2+ sum 3)/3
如果你不想除以2,你也可以乘以一半,这不会改变任何东西,但它只是另一种选择。
(sum 1+ sum 2+ sum 3)*1/2
请记住您想要划分的内容。如果是更多术语,请利用分组符号!
{Rich}