让我们说,我有两个功能依赖
A -> EF
B -> GH
我们可以通过哪些公理来推断下面的关系?
AB -> EFGH
答案 0 :(得分:2)
你可以推导出:
AB -> EFGH
从:
A -> EF
B -> GH
执行以下步骤:
1. A -> EF (by hypothesis)
2. B -> GH (by hypothesis)
3. AB -> BEF (by augmentation, adding B to the left and right part of 1)
4. AB -> AGH (by augmentation, adding A to the left and right part of 2)
5. AB -> ABEFGH (by union)
6. AB -> EFGH (by decomposition)
答案 1 :(得分:0)
我不确定你想做什么。
但是使用生病的样本我可以将我的工作与地理数据联系起来因为有类似的东西
我有起始点Ep
和端点 Sp -> x1y1
Ep -> x2y2
SpEp
我有一条线,在这种情况下 SpEp -> x1y1x2y2
是唯一的
SpEp
但在那一刻line_id
成为@echo off
setlocal
cls
echo enter your name
echo name:
echo enter name above
rem Move cursor to one line below screen size,
rem you must adjust this value to fit your screen.
for /L %%i in (1,1,34) do echo/
rem Move cursor to screen home and hide timeout "Waiting..." message
for /F %%a in ('timeout /T 1 ^> CON') do rem
set /P "name=name: "
echo/
echo/
echo/
echo Name read: "%name%"
但我几乎不会称之为公理。