我正在尝试使用lsegal https://github.com/lsegal/my_toy_compiler的my_toy_compiler,但是当我尝试“编译”它时,我得到48个shift / reduce错误。
我解决了24个shift / reduce错误,将此行添加到parser.y文件中:
%left TCEQ TCNE TCLT TCLE TCGT TCGE
但我仍然得到24错误,我没有想到如何解决它。
%{
#include "node.h"
#include <cstdio>
#include <cstdlib>
NBlock *programBlock; /* the top level root node of our final AST */
extern int yylex();
void yyerror(const char *s) { std::printf("Error: %s\n", s);std::exit(1); }
%}
/* Represents the many different ways we can access our data */
%union {
Node *node;
NBlock *block;
NExpression *expr;
NStatement *stmt;
NIdentifier *ident;
NVariableDeclaration *var_decl;
std::vector<NVariableDeclaration*> *varvec;
std::vector<NExpression*> *exprvec;
std::string *string;
int token;
}
/* Define our terminal symbols (tokens). This should
match our tokens.l lex file. We also define the node type
they represent.
*/
%token <string> TIDENTIFIER TINTEGER TDOUBLE
%token <token> TCEQ TCNE TCLT TCLE TCGT TCGE TEQUAL
%token <token> TLPAREN TRPAREN TLBRACE TRBRACE TCOMMA TDOT
%token <token> TPLUS TMINUS TMUL TDIV
%token <token> TRETURN TEXTERN
/* Define the type of node our nonterminal symbols represent.
The types refer to the %union declaration above. Ex: when
we call an ident (defined by union type ident) we are really
calling an (NIdentifier*). It makes the compiler happy.
*/
%type <ident> ident
%type <expr> numeric expr
%type <varvec> func_decl_args
%type <exprvec> call_args
%type <block> program stmts block
%type <stmt> stmt var_decl func_decl extern_decl
%type <token> comparison
/* Operator precedence for mathematical operators */
%left TPLUS TMINUS
%left TMUL TDIV
%left TCEQ TCNE TCLT TCLE TCGT TCGE
%start program
%%
program : stmts { programBlock = $1; }
;
stmts : stmt { $$ = new NBlock(); $$->statements.push_back($<stmt>1); }
| stmts stmt { $1->statements.push_back($<stmt>2); }
;
stmt : var_decl
| func_decl
| extern_decl
| expr { $$ = new NExpressionStatement(*$1); }
| TRETURN expr { $$ = new NReturnStatement(*$2); }
;
block : TLBRACE stmts TRBRACE { $$ = $2; }
| TLBRACE TRBRACE { $$ = new NBlock(); }
;
var_decl : ident ident { $$ = new NVariableDeclaration(*$1, *$2); }
| ident ident TEQUAL expr { $$ = new NVariableDeclaration(*$1, *$2, $4); }
;
extern_decl : TEXTERN ident ident TLPAREN func_decl_args TRPAREN
{ $$ = new NExternDeclaration(*$2, *$3, *$5); delete $5; }
;
func_decl : ident ident TLPAREN func_decl_args TRPAREN block
{ $$ = new NFunctionDeclaration(*$1, *$2, *$4, *$6); delete $4; }
;
func_decl_args : /*blank*/ { $$ = new VariableList(); }
| var_decl { $$ = new VariableList(); $$->push_back($<var_decl>1); }
| func_decl_args TCOMMA var_decl { $1->push_back($<var_decl>3); }
;
ident : TIDENTIFIER { $$ = new NIdentifier(*$1); delete $1; }
;
numeric : TINTEGER { $$ = new NInteger(atol($1->c_str())); delete $1; }
| TDOUBLE { $$ = new NDouble(atof($1->c_str())); delete $1; }
;
expr : ident TEQUAL expr { $$ = new NAssignment(*$<ident>1, *$3); }
| ident TLPAREN call_args TRPAREN { $$ = new NMethodCall(*$1, *$3); delete $3; }
| ident { $<ident>$ = $1; }
| numeric
| expr TMUL expr { $$ = new NBinaryOperator(*$1, $2, *$3); }
| expr TDIV expr { $$ = new NBinaryOperator(*$1, $2, *$3); }
| expr TPLUS expr { $$ = new NBinaryOperator(*$1, $2, *$3); }
| expr TMINUS expr { $$ = new NBinaryOperator(*$1, $2, *$3); }
| expr comparison expr { $$ = new NBinaryOperator(*$1, $2, *$3); }
| TLPAREN expr TRPAREN { $$ = $2; }
;
call_args : /*blank*/ { $$ = new ExpressionList(); }
| expr { $$ = new ExpressionList(); $$->push_back($1); }
| call_args TCOMMA expr { $1->push_back($3); }
;
comparison : TCEQ | TCNE | TCLT | TCLE | TCGT | TCGE;
%%
希望你能帮助我!
答案 0 :(得分:1)
使用-v
选项获取bison以获取汇总语法和所有冲突的y.output
文件。在您的情况下,冲突在很多地方,但您可以依次查看每个冲突。例如,您看到:
State 13
11 var_decl: ident . ident
12 | ident . ident TEQUAL expr
14 func_decl: ident . ident TLPAREN func_decl_args TRPAREN block
21 expr: ident . TEQUAL expr
22 | ident . TLPAREN call_args TRPAREN
23 | ident .
TIDENTIFIER shift, and go to state 1
TEQUAL shift, and go to state 22
TLPAREN shift, and go to state 23
TIDENTIFIER [reduce using rule 23 (expr)]
TLPAREN [reduce using rule 23 (expr)]
$default reduce using rule 23 (expr)
ident go to state 24
告诉您,当它看到identifier
后跟TIDENTIFIER
或TLPAREN
时,它不知道是继续解析为表达式还是声明。< / p>
在这个特定的情况下,它实际上是由stmt
中stmts
之间的语法中没有分隔符引起的歧义 - 所以两个连续的标识符可以是{{ 1}}或两个var_decl
s。 shift的默认解析将导致它尝试将其解析为声明,这可能是不正确的。