合并2个工会的结果

Question

我有2个部分的联合查询。第1部分计算上个月的付款金额，第2部分计算上个月的付款金额。我使用以下查询

  WITH DATA AS(
    (SELECT DA.ID, DDO.CODE, NULL AS PAYMENTS, ABS(SUM(FAT.AMOUNT_IN_DEFAULT_CURRENCY)) AS STATEMENTS --, FPP.AMOUNT_IN_DEFAULT_CURRENCY AS PAYMENTS
    FROM DIM_ACCOUNT  DA 
    JOIN DIM_DATA_OWNER DDO ON DA.DATA_OWNER_ID = DDO.ID
    JOIN FACT_AS_TRANSACTION FAT ON FAT.ACCOUNT_ID = DA.ID
    JOIN DIM_DATE DD ON FAT.VALUE_DATE_ID = DD.ID
    WHERE DD.CAL_DATE >= TO_DATE('2015-09-20', 'YYYY-MM-DD')
    AND FAT.DEBIT_CREDIT_MARK = 'Debit'
    GROUP BY DA.ID, DDO.CODE
    HAVING SUM(FAT.AMOUNT_IN_DEFAULT_CURRENCY) != 0)
    UNION 
    (SELECT DA.ID, DDO.CODE, ABS(COALESCE(SUM(FPP.AMOUNT_IN_DEFAULT_CURRENCY),0)) AS PAYMENTS, NULL
    FROM DIM_ACCOUNT  DA 
    JOIN DIM_DATA_OWNER DDO ON DA.DATA_OWNER_ID = DDO.ID
    JOIN FACT_PAY_PAYMENT FPP ON FPP.ORDERING_ACCOUNT_ID = DA.ID
    JOIN DIM_PAY_PAYMENT_METHOD DPPM ON DPPM.ID = FPP.PAYMENT_METHOD_ID
    JOIN DIM_DATE DD ON FPP.REQUESTED_EXECUTION_DATE_ID = DD.ID
    WHERE DD.CAL_DATE >= TO_DATE('2015-09-20', 'YYYY-MM-DD')
    GROUP BY DA.ID, DDO.CODE)
    )
    SELECT * FROM DATA

这给出了以下输出 我要展示的是1行的报表和付款。所以这个结果应该合并为2行： 你怎么意识到这一点？

Answer 1

如果你真的无法在一个select语句中将它们全部加在一起，那么这个小适应应该有效：

WITH DATA AS(
(SELECT DA.ID, DDO.CODE, 0 AS PAYMENTS, ABS(SUM(FAT.AMOUNT_IN_DEFAULT_CURRENCY)) AS STATEMENTS --, FPP.AMOUNT_IN_DEFAULT_CURRENCY AS PAYMENTS
FROM DIM_ACCOUNT  DA 
JOIN DIM_DATA_OWNER DDO ON DA.DATA_OWNER_ID = DDO.ID
JOIN FACT_AS_TRANSACTION FAT ON FAT.ACCOUNT_ID = DA.ID
JOIN DIM_DATE DD ON FAT.VALUE_DATE_ID = DD.ID
WHERE DD.CAL_DATE >= TO_DATE('2015-09-20', 'YYYY-MM-DD')
AND FAT.DEBIT_CREDIT_MARK = 'Debit'
GROUP BY DA.ID, DDO.CODE
HAVING SUM(FAT.AMOUNT_IN_DEFAULT_CURRENCY) != 0)
UNION 
(SELECT DA.ID, DDO.CODE, ABS(COALESCE(SUM(FPP.AMOUNT_IN_DEFAULT_CURRENCY),0)) AS PAYMENTS, 0 AS STATEMENTS
FROM DIM_ACCOUNT  DA 
JOIN DIM_DATA_OWNER DDO ON DA.DATA_OWNER_ID = DDO.ID
JOIN FACT_PAY_PAYMENT FPP ON FPP.ORDERING_ACCOUNT_ID = DA.ID
JOIN DIM_PAY_PAYMENT_METHOD DPPM ON DPPM.ID = FPP.PAYMENT_METHOD_ID
JOIN DIM_DATE DD ON FPP.REQUESTED_EXECUTION_DATE_ID = DD.ID
WHERE DD.CAL_DATE >= TO_DATE('2015-09-20', 'YYYY-MM-DD')
GROUP BY DA.ID, DDO.CODE)
)
SELECT ID, CODE, SUM(PAYMENTS), SUM(STATEMENTS) FROM DATA
GROUP BY ID, CODE

Answer 2

尝试这样的事情，我在一个查询中加入了它。如果您只能在一个表中包含数据，则使用LEFT OUTER JOIN。

SELECT DA.ID, DDO.CODE, ABS(COALESCE(SUM(FPP.AMOUNT_IN_DEFAULT_CURRENCY),0)) AS PAYMENTS, ABS(SUM(FAT.AMOUNT_IN_DEFAULT_CURRENCY)) AS STATEMENTS 
    FROM DIM_ACCOUNT  DA 
    JOIN DIM_DATA_OWNER DDO ON DA.DATA_OWNER_ID = DDO.ID
    LEFT OUTER JOIN FACT_AS_TRANSACTION FAT ON FAT.ACCOUNT_ID = DA.ID
    LEFT OUTER JOIN FACT_PAY_PAYMENT FPP ON FPP.ORDERING_ACCOUNT_ID = DA.ID
    LEFT OUTER JOIN DIM_DATE DD1 ON FAT.VALUE_DATE_ID = DD1.ID
    LEFT OUTER JOIN DIM_DATE DD2 ON FPP.REQUESTED_EXECUTION_DATE_ID = DD.DD2
    LEFT OUTER JOIN DIM_PAY_PAYMENT_METHOD DPPM ON DPPM.ID = FPP.PAYMENT_METHOD_ID
    WHERE DD1.CAL_DATE >= TO_DATE('2015-09-20', 'YYYY-MM-DD')
    AND DD2.CAL_DATE >= TO_DATE('2015-09-20', 'YYYY-MM-DD')
    AND FAT.DEBIT_CREDIT_MARK = 'Debit'
    GROUP BY DA.ID, DDO.CODE
    HAVING SUM(FAT.AMOUNT_IN_DEFAULT_CURRENCY) != 0 OR SUM(FPP.AMOUNT_IN_DEFAULT_CURRENCY) != 0;