Question

在输入单词值后，我无法弄清楚为什么我的代码没有打印出任何内容。我可以输入一个单词，但在通过while循环进行评估后它不会输出任何内容。你有什么想法？

ai = "eye-"
ae = "eye-"
ao = "ow-"
au = "ow-"
ei = "ay-"
eu = "eh-oo-"
iu = "ew-"
oi = "oy-"
ou = "ow-"
ui = "ooey-"
a = "ah-"
e = "eh-"
i = "ee-"
o = "oh-"
u = "oo-"
p = "p"
k = "k"
h = "h"
l = "l"
m = "m" 
n = "n"

word = input("Please enter a Hawaiian word you want pronounced")
character_count1 = int(0)
character_count2 = int(1)
pronunciation = "" 
while character_count1 < len(word):
    if word[character_count1:character_count2] == ai or word[character_count1:character_count2] == "ae"or word[character_count1:character_count2] == "ao"or word[character_count1:character_count2] == "ei"or word[character_count1:character_count2] == "eu"or word[character_count1:character_count2] == "iu"or word[character_count1:character_count2] == "oi"or word[character_count1:character_count2] == "ou":
        print("your word",pronunciation + word[character_count1:character_count2])
        character_count1 + 2 and character_count2 + 2
    elif word[character_count1:character_count1] == a or word[character_count1:character_count1] == e or word[character_count1:character_count1] == i or word[character_count1:character_count1] == o or word[character_count1:character_count1] == p or word[character_count1:character_count1] == k or word[character_count1:character_count1] == h or word[character_count1:character_count1] == l or word[character_count1:character_count1] == m or word[character_count1:character_count1] == n:
        print("your word",pronunciation + word[character_count1:character_count1] )
        character_count1 + 1 and character_count2 + 1

Answer 1

如果您使用名为dictionary的数据结构（python中的一个非常基本的数据结构），那么您想要实现的目标非常简单。像这样更改数据结构：

let swipeGestureRecognizer = UISwipeGestureRecognizer(target: self, action: "didSwipe:")
        self.view.addGestureRecognizer(swipeGestureRecognizer)

现在您可以使用键（单词）访问值（发音）。

像这样，

dic={"ai" :"eye-","ae" :"eye-","ao":  "ow-","au" :"ow-"......}

你会得到：

dic["ai"]

所以，现在让我们试着找到解决方案：

定义字典。

eye-

获取输入，如果不使用python3

，最好使用raw_input

 dic={"ai" :"eye-","ae" :"eye-","ao":  "ow-","au" :"ow-"......}

用空格分割输入并形成一个列表。

word = raw_input("Please enter a Hawaiian word you want pronounced")

使用lst=word.split()的元素作为字典lst来查找key。遍历列表并检查输入是否与value

的任何键匹配

dic

如果

for i in lst:
    print dic.get(i)

不存在，则会打印

None。

因为，您的要求对我来说并不十分清楚，我已经包含了解决问题所需的所有内容。

因此，在需要的地方使用它们并解决问题。

快乐的编码。

Answer 2

答案和评论中说过“使用字典”的人是对的，但是你不能一次循环输入一个字符，因为你有重叠的匹配。在不查看下一个字符的情况下，您无法判断“a”是否是“ai”或“an”的一部分，并且这些情况的处理方式不同。这是一个完整的解决方案，带有注释，可以处理细微内容，并在遇到非法字符串时提供信息性错误消息。

hawaiian_pronunciation = {
        "ai": "eye-",
        "ae": "eye-",
        "ao": "ow-",
        "au": "ow-",
        "ei": "ay-",
        "iu": "ew-",
        "oi": "oy-",
        "ui": "ooey-",
        "a": "ah-",
        "e": "eh-",
        "i": "ee-",
        "o": "oh-",
        "u": "oo-",
        "p": "p",
        "k": "k",
        "h": "h",
        "l": "l",
        "m": "m",
        "n": "n"
    }

def segment(word, start):
    # we have to consider the longest possible segment first
    # so that hai gets tokenized h-ai instead of h-a-i
    for length in (2,1):
        # check if the length of the segment puts us past the end of the word
        # the upper bound can be equal to the length of the word since the 
        # string[upper_bound] is not actually included in the range
        if start+length > len(word):
            continue 

        # the input segment we are considering
        input = word[start:start+length]
        # is it in our dictionary?
        if input in hawaiian_pronunciation:
            # if it is get the corresponding pronunciation
            output = hawaiian_pronunciation[input]
            # return the output and length for a successful match
            return output, length
    # if no candidate matches, raise an exception describing where you were
    # when you failed to find a match
    raise Exception("cannot match word {} at position {}, bad segment {}",
            word, start, word[start:])

def pronounce(word):
    "generate pronunciation from word"
    # build a list of strings
    out = []
    # we have to use a while loop and an explicit index 
    # because we can jump by one or two spaces depending on the length of the match
    start = 0
    while start < len(word):
        # when we get a match, append the new sound and
        # advance the appropriate number of spaces
        new_sound, length = segment(word, start)
        out.append(new_sound)
        start += length
    return "".join(out)

def main():
    print pronounce("hai")

main()

Python字符串帮助夏威夷语发音

2 个答案: