Question

我正在编写一个应用程序，用于计算橄榄球比赛（2015年橄榄球世界杯，但它可以应用于许多其他基于游泳池的比赛）的游泳池阶段的队伍排名。< / p>

在泳池阶段完成时，积分将根据获胜/抽奖/亏损/奖励积分计算，团队按积分排名。 如果两支或更多球队的积分水平相当，那么两支并列球队相互比赛的比赛的胜者将是排名较高的。一旦这个初始排名完成，其他标准（分数差异），尝试差异，得分，尝试得分）用于完成排名过程。

我编写了一个执行上述所有操作的查询，除了第一个排名标准之外 - 应根据两支球队所在比赛的获胜者订购两个积分级别。

这是我的数据库架构：

[TEAM]        [MATCH]
-TeamId       -MatchId
-TeamName     -HomeTeamId
-Pool         -AwayTeamId
              -HomeTeamScore
              -HomeTeamTries
              -AwayTeamScore
              -AwayTeamTries

以下是我用来计算给定池的排名/排名的SQL Server查询：

WITH PoolResults ([MatchId], [TeamId], [Team], [P], [W], [D], [L], [PF], [PA], [PD], [TF], [TA], [TD], [PTS], [BP]) 
AS (SELECT 
        M.[MatchId], 
        M.[HomeTeamId] AS [TeamId], 
        HT.[TeamName], 
        1 AS [P], 
        CASE WHEN M.[HomeTeamScore] > M.[AwayTeamScore] THEN 1 ELSE 0 END AS [W], 
        CASE WHEN M.[HomeTeamScore] = M.[AwayTeamScore] THEN 1 ELSE 0 END AS [D], 
        CASE WHEN M.[HomeTeamScore] < M.[AwayTeamScore] THEN 1 ELSE 0 END AS [L], 
        M.[HomeTeamScore] AS [PF], 
        M.[AwayTeamScore] AS [PA], 
        (M.[HomeTeamScore] - M.[AwayTeamScore]) AS [PD], 
        M.[HomeTeamTries] AS [TF], 
        M.[AwayTeamTries] AS [TA], 
        (M.[HomeTeamTries] - M.[AwayTeamTries]) AS [TD], 
        CASE 
            WHEN M.[HomeTeamScore] > M.[AwayTeamScore] THEN 4 
            WHEN M.[HomeTeamScore] = M.[AwayTeamScore] THEN 2 
            WHEN M.[HomeTeamScore] < M.[AwayTeamScore] THEN 0 
        END AS [PTS], 
        CASE 
            WHEN ((M.[AwayTeamScore] - M.[HomeTeamScore]) BETWEEN 1 AND 7) AND M.[HomeTeamTries] >= 4 THEN 2 
            WHEN ((M.[AwayTeamScore] - M.[HomeTeamScore]) BETWEEN 1 AND 7) THEN 1 
            WHEN M.[HomeTeamTries] >= 4 THEN 1 
            ELSE 0 
        END AS [BP] 
    FROM 
        Match AS M 
        INNER JOIN Team AS HT 
            ON M.[HomeTeamId] = HT.[TeamId] 
    WHERE 
        M.[HomeTeamScore] IS NOT NULL 
        AND HT.[Pool] = @Pool

    UNION 

    SELECT 
        M.[MatchId], 
        M.[AwayTeamId] AS [TeamId], 
        AT.[TeamName], 
        1 AS [P], 
        CASE WHEN M.[AwayTeamScore] > M.[HomeTeamScore] THEN 1 ELSE 0 END AS [W], 
        CASE WHEN M.[AwayTeamScore] = M.[HomeTeamScore] THEN 1 ELSE 0 END AS [D], 
        CASE WHEN M.[AwayTeamScore] < M.[HomeTeamScore] THEN 1 ELSE 0 END AS [L], 
        M.[AwayTeamScore] AS [PF], 
        M.[HomeTeamScore] AS [PA], 
        (M.[AwayTeamScore] - M.[HomeTeamScore]) AS [PD], 
        M.[AwayTeamTries] AS [TF], 
        M.[HomeTeamTries] AS [TA], 
        (M.[AwayTeamTries] - M.[HomeTeamTries]) AS [TD], 
        CASE 
            WHEN M.[AwayTeamScore] > M.[HomeTeamScore] THEN 4 
            WHEN M.[AwayTeamScore] = M.[HomeTeamScore] THEN 2 
            WHEN M.[AwayTeamScore] < M.[HomeTeamScore] THEN 0 
        END AS [PTS], 
        CASE 
            WHEN ((M.[HomeTeamScore] - M.[AwayTeamScore]) BETWEEN 1 AND 7) AND M.[AwayTeamTries] >= 4 THEN 2 
            WHEN ((M.[HomeTeamScore] - M.[AwayTeamScore]) BETWEEN 1 AND 7) THEN 1 
            WHEN M.[AwayTeamTries] >= 4 THEN 1 
            ELSE 0 
        END AS [BP] 
    FROM 
        Match AS M 
        INNER JOIN Team AS AT 
            ON M.[AwayTeamId] = AT.[TeamId] 
    WHERE 
        M.[AwayTeamScore] IS NOT NULL 
        AND AT.[Pool] = @Pool 
    )

SELECT ROW_NUMBER() 
    OVER (ORDER BY 
            SUM([BP] + [PTS]) DESC, 
            SUM([PD]) DESC, 
            SUM([TD]) DESC, 
            SUM([PF]) DESC, 
            SUM([TF]) DESC) AS [Position], 
    [TeamId], 
    [TeamName], 
    SUM([P]) AS [P], 
    SUM([W]) AS [W], 
    SUM([D]) AS [D], 
    SUM([L]) AS [L], 
    SUM([PF]) AS [PF], 
    SUM([PA]) AS [PA], 
    SUM([PD]) AS [PD], 
    SUM([TF]) AS [TF], 
    SUM([TA]) AS [TA], 
    SUM([BP]) AS [BP], 
    SUM([BP] + [PTS]) AS [PTS] 
FROM 
    PoolResults 
GROUP BY 
    [TeamId], 
    [TeamName];

如前所述，除了在两队之间赢得比赛的人之外，这一切都会考虑到两支队伍在同一点上的排名。 是否有人建议如何进行此初始排名？

=====更新为原始帖子=====

澄清 - 在同等积分上可以有超过2支球队，在这种情况下，必须评估2支球队的每个组合以确定排名。 SqlFiddle上的以下示例说明了一个池中有5个团队的场景，其中3个团队的点数相同 - http://sqlfiddle.com/#!6/c0701/3

查询＃1显示原始匹配数据（所参加的球队和得分）

查询＃2显示未排序的池名称：

Australia (10)
England (10)
Fiji (5)
Uruguay (0)
Wales (10)

查询＃3显示了按积分排序的泳池排名：

Australia (10)
England (10)
Wales (10)
Fiji (5)
Uruguay (0)

但是，真正的顺序应该是：

Wales (10)
England (10)
Australia (10)
Fiji (5)
Uruguay (0)

威尔士排名高于英格兰，因为威尔士击败英格兰队，英格兰队排名高于澳大利亚，因为英格兰击败了澳大利亚队

Answer 1

这很复杂，但我会尝试以下方法。

查看对手的每个组合以及谁赢得领带。
将当前排名的结果添加到先前玩家的列中，使用窗口函数添加前一列的列，下一列的列
加入步骤1中的视图
制作一个案例陈述，只有在先前等级或下一等级等于具有步骤1中视图的值的情况下才设置值。
按排名和第4步中的列排序

Answer 2

这需要sql 2012+使用LEAD()和LAG() functions，此时只需要两个团队具有相同的Rank。

<强> SCHEMA

CREATE TABLE Table1
    ([team] varchar(1), [rank] int);

INSERT INTO Table1
    ([team], [rank])
VALUES
    ('A', 1),('B', 1),('C', 2);

CREATE TABLE Table2
    ([team1] varchar(1), [team2] varchar(1), [win] varchar(1));

INSERT INTO Table2
    ([team1], [team2], [win])
VALUES
    ('A', 'B', 'B'), ('C', 'A', 'A'),('C', 'B', 'B');

<强> SQL Fiddle Demo

WITH breakTie AS ( 
    SELECT
        [team],
        [rank],
        LAG([team]) OVER (ORDER BY [rank]) PreviousTeam,
        LEAD([team]) OVER (ORDER BY [rank]) NextTeam,
        LAG([rank]) OVER (ORDER BY [rank]) PreviousRank,
        LEAD([rank]) OVER (ORDER BY [rank]) NextRank
    FROM Table1
)
SELECT *, CASE 
       WHEN B.[rank] = B.[NextRank] and B.[team] = T.[win] THEN 1
       WHEN B.[rank] = B.[PreviousRank] and B.[team] = T.[win] THEN 1
       ELSE 0
    END as breakT
FROM breakTie B
LEFT JOIN Table2 T
   ON ( B.team = T.team1 or B.team = T.team2)
  AND ( B.NextTeam = T.team1 or B.NextTeam = T.team2)
ORDER BY 
    [rank],
    CASE 
       WHEN B.[rank] = B.[NextRank] and B.[team] = T.[win] THEN 1
       WHEN B.[rank] = B.[PreviousRank] and B.[team] = T.[win] THEN 1
       ELSE 0
    END

Answer 3

我想补充一些其他建议。因为您当前的问题存在一些矛盾，并且可能没有适当的回答与当前规则。

第一张图片4队伍同等级别。如果使用前4行的信息。你得到一个职位D, A, B, C，但最后两个不能强制执行。
- 在NFL，他们有一些称为inside conference win的抢七局。因此，您可以计算每个团队在这个团队中获得多少胜利作为一种秩序。
- 所以现在所有条件都是对比。
- 在这种情况下，A和D赢得更多，D击败A.
- 现在C击败B和A击败C.而且你有一个真实的订单。
但如图2所示，你可以让每个人都以2胜。

我的猜测是你应该分析这些限制。也许规则的顺序是不同的，你可以将 THIS 问题减少到只有两个团队合作的问题。

根据谁赢得他们所玩的游戏，对游泳池中的积分进行排名

3 个答案: