基于得分和时间的MySQL排名

Question

我有两个MySQL表如下

表：得分

表：用户

我的要求是对得分进行排名并检索得分total_score是否大于某个值（例如，如果total_score小于15，则排名所有得分）。如果分数相等，那么也要考虑时间。

我编写了以下查询来获取包括排名在内的行（我对SQL查询并不熟悉，但我试图找到一种方法来做到这一点 - 没有运气）。

尝试 - 1

SELECT score.total_score,
       CONCAT(users.user_first_name,' ', users.user_last_name) AS name,
       users.user_email,
       FIND_IN_SET(total_score,
                     (SELECT GROUP_CONCAT(total_score
                                          ORDER BY total_score ASC)
                      FROM score)) AS rank
FROM score
INNER JOIN users ON score.user_id = users.user_id
WHERE score.total_score > 15
ORDER BY score.total_score DESC LIMIT 10

尝试 - 2

SET @Rank := 0;
SELECT score.total_score,score.time,
       CONCAT(users.user_first_name,' ', users.user_last_name) AS name,
       users.user_email,
       @Rank := @Rank + 1 AS rank
FROM score
INNER JOIN users ON score.score_id = users.user_id
WHERE score.total_score > 15
ORDER BY score.total_score DESC, time ASC LIMIT 10

两次尝试均失败，简而言之，我试图做的是，

通过考虑时间（有可能获得相同分数），根据total_score对用户分数进行排名。

提前致谢。

Answer 1

你可以试试这个。 ORDER BY (score.total_score/score.time)

SET @Rank := 0;
SELECT score.total_score, score.time,
       CONCAT(users.user_first_name,' ', users.user_last_name) AS name,
       users.user_email,
       (@Rank := @Rank + 1) AS rank
FROM score
INNER JOIN users ON score.user_id = users.user_id
WHERE score.total_score > 15
ORDER BY (score.total_score/score.time) ASC LIMIT 10