XPath - 选择所有未赢得比赛的球队教练

时间:2013-06-08 21:46:57

标签: xpath

我有一个包含两种元素的XML文件:

<team name="n1" coach="c1"></team>

<game teams="t1 t2" winner="t2"></game>

我想选择那些没有赢过任何比赛的球队的教练。 我试过的是

//team[count(//game[@winner=@name])=0]/@coach

但它不起作用。

3 个答案:

答案 0 :(得分:2)

尝试

//team[not(@name=//game/@winner)]/@coach

选择

COACHES OF ANY TEAM
//team                           /@coach
      THAT DOES NOT
      [not(                    )]
           HAVE A @NAME EQUAL TO ANY @WINNER
           @name=//game/@winner

答案 1 :(得分:0)

这将为您提供未赢得任何比赛的球队教练,包括未分配给任何球队的教练。

//coach[not(@name=//team[@name=//game/@winner]/@coach)]

答案 2 :(得分:0)

我知道它可能看起来有点过分,但您可以使用MS SQL 2005/2008 Express来测试您的xpath。 或者您可以使用http://sqlfiddle.com在线测试。

见这个例子:

DECLARE @xml XML
SET @xml ='<db>
            <team name="chelsea" coach="mourinho"><owner>abramovich</owner><owner>abramovich2</owner></team>
            <team name="arsenal" coach="venger"><owner>poorguy</owner></team>
            <team name="manchester" coach="ferguson"><owner>richguy</owner></team>
            <coach name="mourinho"></coach>
            <coach name="venger"></coach>
            <coach name="ferguson"></coach>
            <coach name="nobody"></coach>
            <game teams="chelsea arsenal" winner="arsenal"></game>
            <game teams="manchester arsenal" winner="manchester"></game>
    </db>'

SELECT 
  name = x.value('@name','varchar(100)')
, element = x.query('.') 
FROM @xml.nodes('//coach[not(@name=//team[@name=//game/@winner]/@coach)]')  AS T(x)

-- OUTPUT
name        element
mourinho    <coach name="mourinho" />
nobody      <coach name="nobody" />