Question

我编写了一个使用Java程序控制Arduino over serial的系统。 Arduino从Java程序接收char并基于char执行基于预编程的操作。当我使用Arduino Programmer串行监视器发送字符时，Arduino完全按预期工作，但当我尝试从Java发送相同的字符时，Arduino没有响应。

这是Arduino代码：

void setup() {
  Serial.begin(9600);
}

void loop() {
  if (Serial.available() == 1) {
    char serialData = Serial.read();   

    // Activate servos based on input
    switch (serialData) {
        case '1':
            activateServo();
            break;

        case '2':
            readSensor1();
            break;

        case '3':
            readSensor2();
            break;

        default:
            // Ignore input
            break;

    }
  }
}


void activateServo() {
    // Code removed
}

void readSensor1() {
    // Code removed
}

void readSensor2() {
    // Code removed
}

这是Java代码。请注意，我使用jSerialComm API：

import java.io.PrintWriter;
import java.time.Duration;
import java.time.Instant;

import com.fazecast.jSerialComm.SerialPort;

public class SerialWriteTest {
    private static char dataToSend = '1';

    public static void main(String[] args) {
        // Find all available ports
        SerialPort[] computerPorts = SerialPort.getCommPorts();

        // Select COM3
        SerialPort selectedPort = null;

        for (SerialPort p : computerPorts) {
            if (p.getSystemPortName().equals("COM3")) {
                selectedPort = p;
            }
        }

        // Try to open port, terminate execution if not possible
        if (selectedPort == null) {
            return;

        } else if (selectedPort.openPort()) {
            System.out.println(selectedPort.getSystemPortName() + " successfully opened.");

        } else {
            System.out.println(selectedPort.getSystemPortName() + " failed to open.");
            return;
        }

        // Set port to scanner mode
        selectedPort.setComPortTimeouts(SerialPort.TIMEOUT_SCANNER, 0, 0);

        // Read from port and display
        try (PrintWriter output = new PrintWriter(selectedPort.getOutputStream())) {
            // Wait for 100 ms
            Instant start = Instant.now();
            while (Duration.between(start, Instant.now()).toMillis() < 100) {}

            try {
                output.write('1');
                output.flush();
                System.out.println("Sent");

            } catch (Exception e) {
                System.out.println("Failed to send");
            }
        }

        selectedPort.closePort();

        System.out.println("--- Main finished ---");
    }
}

由于Arduino似乎正在使用串行监视器，我确定该程序在Java程序中。任何人都可以看到为什么Java程序似乎没有发送角色＆＃39; 1＆＃39;喜欢它应该？

使用Java通过串行

0 个答案: