Question

如果一个浮点变量有5位数，其他浮点数有4位，并且对它们执行算术运算，我的代码就不会像我预期的那样运行。例如：

def capacity(self):

    mmax = self.mmax.get()
    current = self.current.get()
    mmin = self.mmin.get()

    flag = False

    if flag is False:
        if mmax.isdigit() and mmin.isdigit() and current.isdigit():
            capacity = float(100 * ((float(current) - float(mmin)) / (float(mmax) - float(mmin))))
            if mmin <= current <= mmax and 0 <= capacity <= 100:
                flag = True
            else:
                self.result = str("Please ensure the values entered correspond to the correct value.")
        else:
            self.result = str("Please enter only positive integers.")

    if flag is True:
        self.result = "Capacity: %2.2f" % capacity + '%'

如果mmax = 10000, current = 5000, and mmin = 1000，self.result = str("Please ensure...") 如果mmax = 9999, current = 5000, and mmin = 1000，self.result = str("Capacity: 44.45%)。

这里发生了什么/我如何克服这个问题？

Answer 1

我猜测<h1 style="text-align: center"; font-family="MinecrafterReg.ttf">Welcome to Ben's Minecraft</h1>和mmin以及current是字符串。在这种情况下，这个表达式：

mmax

......正在对这些值进行词典比较。这与数字比较不同：例如，if mmin <= current <= mmax and 0 <= capacity <= 100:的计算结果为False，因为“5”大于“1”。

在对值进行比较之前将值转换为数字。

"5000" < "10000"

或者

if mmax.isdigit() and mmin.isdigit() and current.isdigit():
    mmax = float(mmax)
    current = float(current)
    mmin = float(mmin)

    capacity = float(100 * ... #etc

对不同大小的浮点值执行算术运算

1 个答案: