Question

AttributeError: 'list' object has no attribute 'isdigit'

这是我一直接受的持续性错误，我正在搜索数据并获取人名，表格和分数，我试图将分数变为平均值，

pls enter a fullname >> Geoffrey Chiasson
Geoffrey Chiasson   F   6   1   3

我正试图从中获得6 1和3。

这是我的代码：

def searchQuerySurname(alist):
    searchQuery = [ ]
    nofound = 0 ## no found set at 0
    surname = input("pls enter a fullname >> ") ## asks user for surname
    surname = surname.lower() ## converts to lower case
    for row in alist:
        if row[0].lower() == surname: ## surname appears in row0
              searchQuery.append(row) ## appends results
              numbers =int(filter(searchQuery.isdigit, str1))
              nofound = nofound + 1 ## increments variable
    if nofound == 0:
        print("there were no matches") 
    return searchQuery

我崩溃时得到了这个：

AttributeError: 'list' object has no attribute 'isdigit'

Answer 1

您尝试将字符串方法isdigit应用于列表：

>>> 'abc'.isdigit()
False
>>> '123'.isdigit()
True
>>> [].isdigit()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
AttributeError: 'list' object has no attribute 'isdigit'

您应该将检查isdigit应用于不列出searchQuery，而是应用于列表的每个元素（string)。

Answer 2

var getMax = function(){
var content = $("#content");
return content.height();
}

首先使用map(int, filter(str.isdigit, searchQuery))过滤searchQuery，然后将str.isdigit应用于每个剩余的结果。

AttributeError：'list'对象没有属性'isdigit'从找到的数据中提取数字

2 个答案: