我在默认IDE中运行python 3。
这是我的代码:
def print_():
f = open("height.txt","r")
content = f.read()
print(content)
f.close()
main()
def main():
name = str(input("What is your name?"))
data = int(input("How tall are you? (CM)"))
if data.isdigit() == True:
print("\n")
elif data.isdigit() == False:
print("Must be a number!")
main()
# a+ is read only mode
f = open("height.txt","a+")
f.write(name)
f.write(str(data))
f.write("cm, ")
f.close()
data_1 = str(input("1 = View Contents. Other = Quit"))
if data_1 == '1':
print_()
else:
print("Exiting")
main()
答案 0 :(得分:1)
您正在尝试检查isdigit()
您已投放到int的数据。将其作为str
阅读,然后在您检查了它之后进行投射:
def main():
name = str(input("What is your name?"))
data = str(input("How tall are you? (CM)"))
while !data.isdigit():
print("Must be a number!")
data = str(input("How tall are you? (CM)"))
print("\n")
data = int(data)
print("\n")
这个循环将继续请求一个int,直到提供一个,然后将其转换为int
答案 1 :(得分:0)
问题是isdigit对字符串进行操作;但是你已经将数据对象转换为int:data = int(输入(“你有多高?(CM)”))。如果要使用isdigit函数,则应该将数据设为字符串。 data = str(输入(“...”))