我有一个数据框
"X1" "X2" "X3" "X4" "X5" "X6" "X7" "X8" "X9" "X10" "X11" "X12" "X13" "X14" "X15" "X16" "X17" "X18" "X19" "X20" "X21" "X22" "X23" "X24"
13062 145 9 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
586717 66068 18713 7105 3188 1506 750 460 251 141 81 41 39 14 12 6 1 0 1 0 0 0 0 0
55893 1371 155 43 9 3 3 2 0 2 0 1 0 1 0 1 0 0 0 0 0 0 0 0
63123 2573 266 35 10 6 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
14258 63 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
751302 43884 6109 1280 368 123 36 18 6 0 2 1 0 0 0 0 0 0 0 0 0 0 0 0
45018 1017 89 10 6 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
182932 6581 941 238 73 43 20 9 6 8 2 1 1 0 0 1 0 1 0 0 0 0 0 0
23741 356 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
4391 15 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
20201 546 75 17 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
48193 943 50 9 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
11284 89 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
4819 48 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
我找到了每一行的意思
df$mean=apply(df,1,mean)
"X1" "X2" "X3" "X4" "X5" "X6" "X7" "X8" "X9" "X10" "X11" "X12" "X13" "X14" "X15" "X16" "X17" "X18" "X19" "X20" "X21" "X22" "X23" "X24" "mean"
13062 145 9 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 550.75
586717 66068 18713 7105 3188 1506 750 460 251 141 81 41 39 14 12 6 1 0 1 0 0 0 0 0 28545.5833333333
55893 1371 155 43 9 3 3 2 0 2 0 1 0 1 0 1 0 0 0 0 0 0 0 0 2395.16666666667
63123 2573 266 35 10 6 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2750.54166666667
14258 63 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 596.875
751302 43884 6109 1280 368 123 36 18 6 0 2 1 0 0 0 0 0 0 0 0 0 0 0 0 33463.7083333333
45018 1017 89 10 6 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1922.5
182932 6581 941 238 73 43 20 9 6 8 2 1 1 0 0 1 0 1 0 0 0 0 0 0 7952.375
23741 356 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 1004.20833333333
4391 15 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 183.583333333333
20201 546 75 17 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 868.333333333333
48193 943 50 9 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 2049.79166666667
11284 89 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 473.916666666667
4819 48 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 202.875
我想在第1列到第24列的范围内找出平均值所在的位置。
例如：
如果我的x值为1,2,3,4，y为10,20,30,40。如果我在x中找到对应于15的值，我会得1.5。这里我想找出平均值所在的位置，它可以给我一个浮点数，指定它位于列，例如1.5。
更新：
样本数据
X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 mean
10 20 30 40 50 60 70 80 90 100 55
这意味着5.5。如何计算上表中类似的东西。
可以假设每行中的值都已排序。
答案 0 :(得分：0)
df<-read.table(text="X1 X2 X3 X4 X5 X6 X7 X8 X9 X10 X11 X12 X13 X14 X15 X16 X17 X18 X19 X20 X21 X22 X23 X24
13062 145 9 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
586717 66068 18713 7105 3188 1506 750 460 251 141 81 41 39 14 12 6 1 0 1 0 0 0 0 0
55893 1371 155 43 9 3 3 2 0 2 0 1 0 1 0 1 0 0 0 0 0 0 0 0
63123 2573 266 35 10 6 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
14258 63 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
751302 43884 6109 1280 368 123 36 18 6 0 2 1 0 0 0 0 0 0 0 0 0 0 0 0
45018 1017 89 10 6 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
182932 6581 941 238 73 43 20 9 6 8 2 1 1 0 0 1 0 1 0 0 0 0 0 0
23741 356 4 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
4391 15 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
20201 546 75 17 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
48193 943 50 9 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
11284 89 1 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
4819 48 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0",header=T)
df$mean<-rowMeans(df)
n<-ncol(x)
apply(df,1,function(x) (max(which(x[n]<x[-n]))+min(which(x[n]>x[-n])))/2)
[1] 1.5 2.5 1.5 1.5 1.5 2.5 1.5 1.5 1.5 1.5 1.5 1.5 1.5 1.5