在周期

时间:2015-08-25 15:26:47

标签: c# accord.net

我正在使用accord.math来解决具有非线性约束的系统。在这个例子中,约束有4个变量, x => x[0] + x[1] + x[2] + x[3] <= 1但是如果约束应该包括50个变量。如何在周期中构建, x => x[0] + x[1] + x[2] + ...+ x[50] <= 1

namespace ConsoleApplication21
{
class Program
{
    static void Main(string[] args)
    {

        var f = new NonlinearObjectiveFunction(4, x => 0.010 * x[0] - 0.000543 * x[1] - 0.003440 * x[2] + 0.000292 * x[3]);

        var constraints = new[]
        {
           new NonlinearConstraint(4, x => x[0] + x[1] + x[2] + x[3] <= 1),
           new NonlinearConstraint(4, x => x[0] + x[1] + x[2] + x[3] >= 1),

        };

        var cobyla = new Cobyla(f, constraints);

        bool success = cobyla.Maximize();
        double minimum = cobyla.Value;        
        double[] solution = cobyla.Solution;
        Console.WriteLine(minimum);
    }
}
}

1 个答案:

答案 0 :(得分:1)

如果你需要的只是数组中所有值的总和,你可以使用LINQ的Sum()方法,如下所示:

new NonlinearConstraint(x.Length, x => x.Sum() >= 1)

通常,您可以使用LINQ&#39; Enumerable.Range替换循环。例如,要将x[first]添加到x[first+count-1],请使用以下表达式:

new NonlinearConstraint(
    x.Length
,   x => Enumerable.Range(first, count).Select(i => x[i]).Sum() >= 1
)