Question

嗨，我尝试在c ++中打印以下模式

使用以下循环打印一半。

int i,j,k=1;
cout<<"Enter row";
cin>>n;
for(i=1;i<=n;i++)
{
  for(j=1;j<=i;j++)
  {
    cout<<k<<"\t";
    k++;
  }
}

我得到了像

这样的输出

如何打印平衡输出。但我怎样才能打印出这种模式的镜子。

Answer 1

首先，上面的代码是错误的，它应该是：

for(i=1;i<=n;i++)
{
  for(j=1;j<=i;j++)
  {
    cout<<k<< " ";
    k++;
  }

  cout << '\n';
}

现在，要绘制模式，您可以使用一个使用以下逻辑的循环：

for(;i > 0; i--)
{
    k -= i-1;

    for(j=1;j<i;j++)
    {
        cout <<k<< " ";
        k++;
    }

    cout << '\n';
    k -= i-1;
}

Answer 2

int main()
{
    int n;
    int i, j, k = 1;
    cout << "Enter row";
    cin >> n;
    int elemcount = 0;
    for (i = 1; i <= n; i++)
    {
        elemcount = 0;
        for (j = 1; j <= i; j++)
        {

            cout << k << "\t";
            k++;
        }
        cout <<endl;
    }
    k = k - n;      //Reset Counter to the value of the first digit in current row.
    i--;
    j--;
    for (; i > 0; i--)
    {
        j = i;
        elemcount = 0;          //Counter to keep track of elements printed.
        for (; j> 0; j--)
        {
            cout << k << "\t";
            k++;
            elemcount++;
        }
        k = k - elemcount - (i-1); //Resetting K, substracting the number of elements printed and number of elements to be printed in next row.
        cout << endl;
    }

    return 0;
}

C ++中的Floyd模式

2 个答案: