这是一个非常简洁的方法！

Question

我需要将秒数转换为“小时：分钟：秒”。

例如：“685”转换为“00:11:25”

我怎样才能做到这一点？

Answer 1

您可以使用gmdate()功能：

echo gmdate("H:i:s", 685);

Answer 2

一小时是3600秒，一分钟是60秒，为什么不呢：

<?php

$init = 685;
$hours = floor($init / 3600);
$minutes = floor(($init / 60) % 60);
$seconds = $init % 60;

echo "$hours:$minutes:$seconds";

?>

产生：

$ php file.php
0:11:25

（我没有测试过这么多，因此可能会出现地板错误等）

Answer 3

你去吧

function format_time($t,$f=':') // t = seconds, f = separator 
{
  return sprintf("%02d%s%02d%s%02d", floor($t/3600), $f, ($t/60)%60, $f, $t%60);
}

echo format_time(685); // 00:11:25

Answer 4

仅当秒小于gmdate()（1天）时才使用函数86400 ^：

$seconds = 8525;
echo gmdate('H:i:s', $seconds);
# 02:22:05

请参阅：gmdate()

Run the Demo

通过'foot'^无限制*：

将秒转换为格式

$seconds = 8525;
$H = floor($seconds / 3600);
$i = ($seconds / 60) % 60;
$s = $seconds % 60;
echo sprintf("%02d:%02d:%02d", $H, $i, $s);
# 02:22:05

请参阅：floor()，sprintf()，arithmetic operators

Run the Demo

使用DateTime扩展程序的示例：

$seconds = 8525;
$zero    = new DateTime("@0");
$offset  = new DateTime("@$seconds");
$diff    = $zero->diff($offset);
echo sprintf("%02d:%02d:%02d", $diff->days * 24 + $diff->h, $diff->i, $diff->s);
# 02:22:05

请参阅：DateTime::__construct()，DateTime::modify()，clone， sprintf()

Run the Demo

MySQL示例^{范围的结果被限制为TIME数据类型的范围，从-838:59:59到838:59:59}：

SELECT SEC_TO_TIME(8525);
# 02:22:05

请参阅：SEC_TO_TIME

Run the Demo

PostgreSQL示例：

SELECT TO_CHAR('8525 second'::interval, 'HH24:MI:SS');
# 02:22:05

Run the Demo

Answer 5

其他解决方案使用gmdate，但在有超过86400秒的边缘情况下失败。为了解决这个问题，我们可以简单地计算自己的小时数，然后让gmdate将剩余的秒数计算为分钟/秒。

echo floor($seconds / 3600) . gmdate(":i:s", $seconds % 3600);

输入：6030 输出：1:40:30

输入：2000006030 输出：555557:13:50

Answer 6

// TEST
// 1 Day 6 Hours 50 Minutes 31 Seconds ~ 111031 seconds

$time = 111031; // time duration in seconds

$days = floor($time / (60 * 60 * 24));
$time -= $days * (60 * 60 * 24);

$hours = floor($time / (60 * 60));
$time -= $hours * (60 * 60);

$minutes = floor($time / 60);
$time -= $minutes * 60;

$seconds = floor($time);
$time -= $seconds;

echo "{$days}d {$hours}h {$minutes}m {$seconds}s"; // 1d 6h 50m 31s

Answer 7

gmdate("H:i:s", no_of_seconds);

如果H:i:s大于1天（一天中的秒数），则不会以no_of_seconds格式提供时间。
它将忽略日值并仅提供Hour:Min:Seconds

例如：

gmdate("H:i:s", 89922); // returns 0:58:42 not (1 Day 0:58:42) or 24:58:42

Answer 8

这是一个处理负秒和超过1天秒的衬里。

sprintf("%s:%'02s:%'02s\n", intval($seconds/60/60), abs(intval(($seconds%3600) / 60)), abs($seconds%60));

例如：

$seconds= -24*60*60 - 2*60*60 - 3*60 - 4; // minus 1 day 2 hours 3 minutes 4 seconds
echo sprintf("%s:%'02s:%'02s\n", intval($seconds/60/60), abs(intval(($seconds%3600) / 60)), abs($seconds%60));

输出：-26：03：04

Answer 9

写这样的函数来返回一个数组

function secondsToTime($seconds) {

  // extract hours
  $hours = floor($seconds / (60 * 60));

  // extract minutes
  $divisor_for_minutes = $seconds % (60 * 60);
  $minutes = floor($divisor_for_minutes / 60);

  // extract the remaining seconds
  $divisor_for_seconds = $divisor_for_minutes % 60;
  $seconds = ceil($divisor_for_seconds);

  // return the final array
  $obj = array(
      "h" => (int) $hours,
      "m" => (int) $minutes,
      "s" => (int) $seconds,
   );

  return $obj;
}

然后简单地调用这个函数：

secondsToTime(100);

输出

Array ( [h] => 0 [m] => 1 [s] => 40 )

Answer 10

请参阅：

    /** 
     * Convert number of seconds into hours, minutes and seconds 
     * and return an array containing those values 
     * 
     * @param integer $inputSeconds Number of seconds to parse 
     * @return array 
     */ 

    function secondsToTime($inputSeconds) {

        $secondsInAMinute = 60;
        $secondsInAnHour  = 60 * $secondsInAMinute;
        $secondsInADay    = 24 * $secondsInAnHour;

        // extract days
        $days = floor($inputSeconds / $secondsInADay);

        // extract hours
        $hourSeconds = $inputSeconds % $secondsInADay;
        $hours = floor($hourSeconds / $secondsInAnHour);

        // extract minutes
        $minuteSeconds = $hourSeconds % $secondsInAnHour;
        $minutes = floor($minuteSeconds / $secondsInAMinute);

        // extract the remaining seconds
        $remainingSeconds = $minuteSeconds % $secondsInAMinute;
        $seconds = ceil($remainingSeconds);

        // return the final array
        $obj = array(
            'd' => (int) $days,
            'h' => (int) $hours,
            'm' => (int) $minutes,
            's' => (int) $seconds,
        );
        return $obj;
    }

来自：Convert seconds into days, hours, minutes and seconds

Answer 11

gmtdate（）函数对我不起作用，因为我正在跟踪项目的工作时间，如果超过24小时，则会减去24小时后剩余的金额。换句话说，37小时变为13小时。（如上所述，格拉维奇 - 感谢你的例子！）这个很好用：

Convert seconds to format by 'foot' no limit :
$seconds = 8525;
$H = floor($seconds / 3600);
$i = ($seconds / 60) % 60;
$s = $seconds % 60;
echo sprintf("%02d:%02d:%02d", $H, $i, $s);
# 02:22:05

Answer 12

这个功能我很有用，你可以扩展它：

function formatSeconds($seconds) {

if(!is_integer($seconds)) {
    return FALSE;
}

$fmt = "";

$days = floor($seconds / 86400);
if($days) {
    $fmt .= $days."D ";
    $seconds %= 86400;
}

$hours = floor($seconds / 3600);
if($hours) {
    $fmt .= str_pad($hours, 2, '0', STR_PAD_LEFT).":";
    $seconds %= 3600;
}

$mins = floor($seconds / 60 );
if($mins) {
    $fmt .= str_pad($mins, 2, '0', STR_PAD_LEFT).":";
    $seconds %= 60;
}

$fmt .= str_pad($seconds, 2, '0', STR_PAD_LEFT);

return $fmt;}

Answer 13

如果您不喜欢已接受的答案或受欢迎的答案，请尝试这个

function secondsToTime($seconds_time)
{
    if ($seconds_time < 24 * 60 * 60) {
        return gmdate('H:i:s', $seconds_time);
    } else {
        $hours = floor($seconds_time / 3600);
        $minutes = floor(($seconds_time - $hours * 3600) / 60);
        $seconds = floor($seconds_time - ($hours * 3600) - ($minutes * 60));
        return "$hours:$minutes:$seconds";
    }
}

secondsToTime(108620); // 30:10:20

Answer 14

试试这个：

date("H:i:s",-57600 + 685);

取自
http://bytes.com/topic/php/answers/3917-seconds-converted-hh-mm-ss

Answer 15

在Java中，您可以使用这种方式。

   private String getHmaa(long seconds) {
    String string;
    int hours = (int) seconds / 3600;
    int remainder = (int) seconds - hours * 3600;
    int mins = remainder / 60;
    //remainder = remainder - mins * 60;
    //int secs = remainder;

    if (hours < 12 && hours > 0) {
        if (mins < 10) {
            string = String.valueOf((hours < 10 ? "0" + hours : hours) + ":" + (mins > 0 ? "0" + mins : "0") + " AM");
        } else {
            string = String.valueOf((hours < 10 ? "0" + hours : hours) + ":" + (mins > 0 ? mins : "0") + " AM");
        }
    } else if (hours >= 12) {
        if (mins < 10) {
            string = String.valueOf(((hours - 12) < 10 ? "0" + (hours - 12) : ((hours - 12) == 12 ? "0" : (hours - 12))) + ":" + (mins > 0 ? "0" + mins : "0") + ((hours - 12) == 12 ? " AM" : " PM"));
        } else {
            string = String.valueOf(((hours - 12) < 10 ? "0" + (hours - 12) : ((hours - 12) == 12 ? "0" : (hours - 12))) + ":" + (mins > 0 ? mins : "0") + ((hours - 12) == 12 ? " AM" : " PM"));
        }
    } else {
        if (mins < 10) {
            string = String.valueOf("0" + ":" + (mins > 0 ? "0" + mins : "0") + " AM");
        } else {
            string = String.valueOf("0" + ":" + (mins > 0 ? mins : "0") + " AM");
        }
    }
    return string;
}

Answer 16

解决方案来自：https://gist.github.com/SteveJobzniak/c91a8e2426bac5cb9b0cbc1bdbc45e4b

这是一个非常简洁的方法！

这段代码尽可能地避免了繁琐的函数调用和逐个字符串构建，以及人们为此做出的庞大而笨重的功能。

它生成“1h05m00s”格式，并使用前导零分钟和秒，只要在它们之前有另一个非零时间组件。

它跳过所有空的主要组件，以避免给你无用的信息，如“0h00m01s”（相反，它会显示为“1s”）。

示例结果：“1s”，“1m00s”，“19m08s”，“1h00m00s”，“4h08m39s”。

$duration = 1; // values 0 and higher are supported!
$converted = [
    'hours' => floor( $duration / 3600 ),
    'minutes' => floor( ( $duration / 60 ) % 60 ),
    'seconds' => ( $duration % 60 )
];
$result = ltrim( sprintf( '%02dh%02dm%02ds', $converted['hours'], $converted['minutes'], $converted['seconds'] ), '0hm' );
if( $result == 's' ) { $result = '0s'; }

如果你想让代码更短（但可读性更低），你可以避免使用$converted数组，而是将值直接放在sprintf（）调用中，如下所示：

$duration = 1; // values 0 and higher are supported!
$result = ltrim( sprintf( '%02dh%02dm%02ds', floor( $duration / 3600 ), floor( ( $duration / 60 ) % 60 ), ( $duration % 60 ) ), '0hm' );
if( $result == 's' ) { $result = '0s'; }

上述代码段的两个中的持续时间必须为0或更高。不支持负持续时间。但是，您可以通过使用以下替代代码来处理负持续时间：

$duration = -493; // negative values are supported!
$wasNegative = FALSE;
if( $duration < 0 ) { $wasNegative = TRUE; $duration = abs( $duration ); }
$converted = [
    'hours' => floor( $duration / 3600 ),
    'minutes' => floor( ( $duration / 60 ) % 60 ),
    'seconds' => ( $duration % 60 )
];
$result = ltrim( sprintf( '%02dh%02dm%02ds', $converted['hours'], $converted['minutes'], $converted['seconds'] ), '0hm' );
if( $result == 's' ) { $result = '0s'; }
if( $wasNegative ) { $result = "-{$result}"; }
// $result is now "-8m13s"

Answer 17

使用DateTime的一个简单方法是：

    $time = 60; //sec.
    $now = time();
    $rep = new DateTime('@'.$now);
    $diff = new DateTime('@'.($now+$time));
    $return = $diff->diff($rep)->format($format);

    //output:  01:04:65

这是一个简单的解决方案，使您能够使用DateTime格式的方法。

Answer 18

以下代码可以准确显示总时数加上分钟和秒数

$duration_in_seconds = 86401;
if($duration_in_seconds>0)
{
    echo floor($duration_in_seconds/3600).gmdate(":i:s", $duration_in_seconds%3600);
}
else
{
    echo "00:00:00";
}

Answer 19

这是一个很好的方法：

function time_converter($sec_time, $format='h:m:s'){
      $hour = intval($sec_time / 3600) >= 10 ? intval($sec_time / 3600) : '0'.intval($sec_time / 3600);
      $minute = intval(($sec_time % 3600) / 60) >= 10 ? intval(($sec_time % 3600) / 60) : '0'.intval(($sec_time % 3600) / 60);
      $sec = intval(($sec_time % 3600) % 60)  >= 10 ? intval(($sec_time % 3600) % 60) : '0'.intval(($sec_time % 3600) % 60);

      $format = str_replace('h', $hour, $format);
      $format = str_replace('m', $minute, $format);
      $format = str_replace('s', $sec, $format);

      return $format;
    }

Answer 20

如果您想创建音频/视频持续时间字符串，例如YouTube等，可以执行以下操作：

($seconds >= 60) ? ltrim(gmdate("H:i:s", $seconds), ":0") : gmdate("0:s", $seconds)

将返回如下字符串：

55.55 => '0:55'
100   => '1:40'

可能无法在超过24小时的时间内正常工作。

Answer 21

我已经解释过这个here 将该答案也粘贴在这里

直到 23:59:59 小时，您可以使用 PHP 默认函数

echo gmdate("H:i:s", 86399);

这只会返回结果直到 23:59:59

如果你的秒数大于 86399 在@VolkerK 的帮助下回答

$time = round($seconds);
echo sprintf('%02d:%02d:%02d', ($time/3600),($time/60%60), $time%60);

将是最好的选择...

Answer 22

如果您需要使用JavaScript进行操作，则可以按照Convert seconds to HH-MM-SS with JavaScript此处回答的仅一行代码来完成。将 SECONDS 替换为要转换的内容。

var time = new Date(SECONDS * 1000).toISOString().substr(11, 8);

Answer 23

function timeToSecond($time){
    $time_parts=explode(":",$time);
    $seconds= ($time_parts[0]*86400) + ($time_parts[1]*3600) + ($time_parts[2]*60) + $time_parts[3] ; 
    return $seconds;
}

function secondToTime($time){
    $seconds  = $time % 60;
    $seconds<10 ? "0".$seconds : $seconds;
    if($seconds<10) {
        $seconds="0".$seconds;
    }
    $time     = ($time - $seconds) / 60;
    $minutes  = $time % 60;
    if($minutes<10) {
        $minutes="0".$minutes;
    }
    $time     = ($time - $minutes) / 60;
    $hours    = $time % 24;
    if($hours<10) {
        $hours="0".$hours;
    }
    $days     = ($time - $hours) / 24;
    if($days<10) {
        $days="0".$days;
    }

    $time_arr = array($days,$hours,$minutes,$seconds);
    return implode(":",$time_arr);
}

Answer 24

[x86-64 gcc 8.2 #1] error: could not convert 'a' from
'Matrix<#'nontype_argument_pack' not supported by
dump_expr#<expression error>>' to 'Matrix<#'nontype_argument_pack' not
supported by dump_expr#<expression error>>'

将其转换为函数：

$given = 685;

 /*
 * In case $given == 86400, gmdate( "H" ) will convert it into '00' i.e. midnight.
 * We would need to take this into consideration, and so we will first
 * check the ratio of the seconds i.e. $given:$number_of_sec_in_a_day
 * and then after multiplying it by the number of hours in a day (24), we
 * will just use "floor" to get the number of hours as the rest would
 * be the minutes and seconds anyways.
 *
 * We can also have minutes and seconds combined in one variable,
 * e.g. $min_sec = gmdate( "i:s", $given );
 * But for versatility sake, I have taken them separately.
 */

$hours = ( $given > 86399 ) ? '0'.floor( ( $given / 86400 ) * 24 )-gmdate( "H", $given ) : gmdate("H", $given );

$min = gmdate( "i", $given );

$sec = gmdate( "s", $given );

echo $formatted_string = $hours.':'.$min.':'.$sec;

Answer 25

嗯，我需要能够将秒数减少到几分钟和几秒钟的东西，但是会超过24小时，而不会进一步减少到几天。

这是一个有效的简单功能。你可以改进它......但是这里是：

function formatSeconds($seconds)
{
    $hours = 0;$minutes = 0;
    while($seconds >= 60){$seconds -= 60;$minutes++;}
    while($minutes >= 60){$minutes -=60;$hours++;}
    $hours = str_pad($hours, 2, '0', STR_PAD_LEFT);
    $minutes = str_pad($minutes, 2, '0', STR_PAD_LEFT);
    $seconds = str_pad($seconds, 2, '0', STR_PAD_LEFT);
    return $hours.":".$minutes.":".$seconds;
}

Answer 26

怎么样？

print date('H:i:s', mktime(0, 0, 685, 0, 0));

没有任何扩展

Answer 27

以防万一其他人正在寻找一个简单的函数来返回这个格式很好的（我知道它不是OP要求的格式），这就是我刚刚提出的。感谢@mughal代码，这是基于。

function format_timer_result($time_in_seconds){
    $time_in_seconds = ceil($time_in_seconds);

    // Check for 0
    if ($time_in_seconds == 0){
        return 'Less than a second';
    }

    // Days
    $days = floor($time_in_seconds / (60 * 60 * 24));
    $time_in_seconds -= $days * (60 * 60 * 24);

    // Hours
    $hours = floor($time_in_seconds / (60 * 60));
    $time_in_seconds -= $hours * (60 * 60);

    // Minutes
    $minutes = floor($time_in_seconds / 60);
    $time_in_seconds -= $minutes * 60;

    // Seconds
    $seconds = floor($time_in_seconds);

    // Format for return
    $return = '';
    if ($days > 0){
        $return .= $days . ' day' . ($days == 1 ? '' : 's'). ' ';
    }
    if ($hours > 0){
        $return .= $hours . ' hour' . ($hours == 1 ? '' : 's') . ' ';
    }
    if ($minutes > 0){
        $return .= $minutes . ' minute' . ($minutes == 1 ? '' : 's') . ' ';
    }
    if ($seconds > 0){
        $return .= $seconds . ' second' . ($seconds == 1 ? '' : 's') . ' ';
    }
    $return = trim($return);

    return $return;
}

Answer 28

将来寻找此项目的任何人都会提供初始海报所要求的格式。

$init = 685;
$hours = floor($init / 3600);
$hrlength=strlen($hours);
if ($hrlength==1) {$hrs="0".$hours;}
else {$hrs=$hours;} 

$minutes = floor(($init / 60) % 60);
$minlength=strlen($minutes);
if ($minlength==1) {$mins="0".$minutes;}
else {$mins=$minutes;} 

$seconds = $init % 60;
$seclength=strlen($seconds);
if ($seclength==1) {$secs="0".$seconds;}
else {$secs=$seconds;} 

echo "$hrs:$mins:$secs";

Answer 29

<?php
$time=3*3600 + 30*60;


$year=floor($time/(365*24*60*60));
$time-=$year*(365*24*60*60);

$month=floor($time/(30*24*60*60));
$time-=$month*(30*24*60*60);

$day=floor($time/(24*60*60));
$time-=$day*(24*60*60);

$hour=floor($time/(60*60));
$time-=$hour*(60*60);

$minute=floor($time/(60));
$time-=$minute*(60);

$second=floor($time);
$time-=$second;
if($year>0){
    echo $year." year, ";
}
if($month>0){
    echo $month." month, ";
}
if($day>0){
    echo $day." day, ";
}
if($hour>0){
    echo $hour." hour, ";
}
if($minute>0){
    echo $minute." minute, ";
}
if($second>0){
    echo $second." second, ";
}

将秒转换为小时：分钟：秒

29 个答案:

这是一个非常简洁的方法！