Question

我想创建一个构造函数，它需要几秒钟并将其转换为HH：MM：SS。我可以很容易地用积极的秒数做到这一点，但是我在负秒时遇到了一些困难。

这是我到目前为止所做的：

private final int HOUR, MINUTE, SECOND, TOTAL_TIME_IN_SECONDS;

public MyTime(int timeInSeconds) {
   if (timeInSeconds < 0) {
        //Convert negative seconds to HH:MM:SS
    } else {
        this.HOUR = (timeInSeconds / 3600) % 24;
        this.MINUTE = (timeInSeconds % 3600) / 60;
        this.SECOND = timeInSeconds % 60;
        this.TOTAL_TIME_IN_SECONDS
                = (this.HOUR * 3600)
                + (this.MINUTE * 60)
                + (this.SECOND);
    }
}

如果timeInSeconds为-1，我希望时间返回23:59:59等等。

谢谢！

Answer 1

if (time < 0)
    time += 24 * 60 * 60;

将其添加到构造函数的开头。如果您期望有大的负数，那么在IF中输入。

Answer 2

class MyTime {
  private final int HOUR, MINUTE, SECOND, TOTAL_TIME_IN_SECONDS;
  private static final int SECONDS_IN_A_DAY = 86400;

  public MyTime(int timeInSeconds) {
     prepare(normalizeSeconds(timeInSeconds));
  }

  private int normalizeSeconds(int timeInSeconds) {
      //add timeInSeconds % SECONDS_IN_A_DAY modulo operation if you expect values exceeding SECONDS_IN_A_DAY:  
      //or throw an IllegalArgumentException
      if (timeInSeconds < 0) {
       return SECONDS_IN_A_DAY + timeInSeconds;
     } else {
       return timeInSeconds;
     }
  }

  private prepare(int timeInSeconds) {
        this.HOUR = (timeInSeconds / 3600) % 24;
        this.MINUTE = (timeInSeconds % 3600) / 60;
        this.SECOND = timeInSeconds % 60;
        this.TOTAL_TIME_IN_SECONDS
                = (this.HOUR * 3600)
                + (this.MINUTE * 60)
                + (this.SECOND);
  }

}

Answer 3

怎么样

if (timeInSeconds < 0) {
    return MyTime(24 * 60 * 60 + timeInSeconds);
}

因此它会循环，你会利用现有的逻辑。

您可以使用if循环替换while以避免递归

将负秒转换为小时：分钟：秒

3 个答案: